Lithium-Ion batteries are commonly used in portable electronics and electric vehicles. These rechargeable batteries have two electrodes: one that's positively charged and contains lithium and another negative one that's typically made of graphite.
Answer:
There are 6.87 x 1023 atoms in 1.14 mol SO3, or sulfur trioxide :
The amount of gold in decigrams if 450 micrograms is needed is 4.5 × 10-³ decigrams.
<h3>How to convert micrograms to decigrams?</h3>
According to this question, 450 micrograms of a sample of gold is needed but we only have a mass balance that measures in decigrams.
This means that we are to convert the amount of gold you need to decigrams by comparing the exponents.
The conversion factor of micrograms to decigrams is as follows:
1 micrograms = 1 × 10-⁵ decigrams
This means 450 micrograms is equivalent to 450 × 1 × 10-⁵ = 4.5 × 10-³ decigrams
Therefore, the amount of gold in decigrams if 450 micrograms is needed is 4.5 × 10-³ decigrams.
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Answer:
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Answer:
Maximum height reached by the rocket, h = 202.62 meters
Explanation:
It is given that,
Initial speed of the model rocket, u = 56.5 m/s
Constant upward acceleration, 
Distance traveled by the engine until it stops, d = 198.8 m
Let v is the speed of the rocket when the engine stops. It can be calculated using the third equation of motion as :

v = 63.02 m/s
At the maximum height, v = 0 and the engine now decelerate under the action of gravity, a = -g. Let h is the maximum height reached by the rocket.
Again using third equation of motion as :




h = 202.62 meters
So, the maximum height reached by the rocket is 202.62 meters. Hence, this is the required solution.