Answer:
The answer to your question is the letter D. 2.5 N
Explanation:
The electrostatic force is the same in both directions,
If the electrostatic force on B due to A is 2.5 N, the magnitude of the electrostatic force on A due to B must be 2.5N.
Maybe the direction is different but the magnitude is the same.
a = Δv ÷ t
t = 5 seconds
Δv = v2 - v1
v2 = 0 m/s
v1 = 54 ÷ 3.6 = 15 m/s ----> a = (0 - 15) ÷ 5 = -15 ÷ 5 = -3 m/s²
Answer:<span>Humid air is lighter, so it has lower pressure.
The reason is the molecules of water are H2O, whose molar mass is 18 g/mol.
These molecules displaces molecules of N2 and O2, whose molar masses are:
N2: 2*14g/mol = 28 g/mol, and
O2: 2*16g/mol = 32 g/mol.
Then molecules of 28g/mol and 32 g/mol are being replaced with molecules of 18g/mol, leading to a lower weight of the same volume of air, which results in lower pressure.
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Answer: The observer must walk 0.2897m towards either speaker.
Explanation:
Let us make distance between the two speakers to be =D
frequency emitted by the two speakers in phase=f
v= speed of sound, 343 m/s
λ=wavelength
---- solving for λ, wavelength, using the equation λ=v/f. 343/296
= 1.15878m
Also destructive interference is given as
⎮d1-d2⎮=λ/2
Because the observer should be able to walk far enough to make the distance to one speaker differ from the distance to the other speaker by ½ wavelength.
This will give us
d1-d2= 1.15878 /2
d1-d2=0.5794m
For the distance moved on either side, we have D/2
Therefore 0.5794/2=distance to move on either side. Giving us
0.2897m
In conclusion, This means that the observer has to walk so as to be 0.5794m closer to one speaker from another; this means walking 0.2897m towards either speaker.