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hodyreva [135]
3 years ago
8

Free free free free free free free

Law
2 answers:
mars1129 [50]3 years ago
8 0

Answer:

the answer is free please give me brainliest

Explanation:

Alina [70]3 years ago
7 0

Answer:

where is yr question?????

thx

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Answer:

safe speed for the larger radius track u= √2 v

Explanation:

The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.

Also given that r_1= smaller radius

r_2= larger radius curve

r_2= 2r_1..............i

let u be the speed of larger radius curve

now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=

r

1

mv

2

=

r

2

mu

2

................ii

form i and ii we can write

v^2= \frac{1}{2} u^2v

2

=

2

1

u

2

⇒u= √2 v

therefore, safe speed for the larger radius track u= √2 v

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3 years ago
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