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2 years ago

9

A blank 2-column table with 3 rows. Column 1 is labeled Column A and Column 2 is labeled Column B. A blank graph has label B on

the x-axis and label A on the y-axis. Weather data is collected to analyze wind speed according to temperature. Identify the variables as either input or output to label the table and graph. Column A = Column B = Label A = Label B =

1 answer:

garri49 [273]2 years ago

6 0

A= temperature column B= wind speed. Label A= wind speed label B= Temperature

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andreev551 [17]

7. 539 is the answer of number 7

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3 years ago

Please help me out!

seropon [69]

Answer:

Second option

Third option

Fourth option

Step-by-step explanation:

We have the following quadratic function

$f(x) =(x-1)(x+7)$

Use the distributive property to multiply the expression

$f(x) =x^2+7x-x-7$

$f(x) =x^2+6x-7$

For a function of the form $f (x) = ax ^ 2 + bx + c$ the x coordinate of the vertex is:

$x =-\frac{b}{2a}$

Then in this case the coordinate of the vertex is:

$x =-\frac{6}{2(1)}$

$x =-3$

To obtain the y coordinate of the vertex we evaluate the function at $x = -3$

$f(-3) =(-3)^2+6(-3)-7$

$f(-3) =9-18-7$

$f(-3) =-16$

Then the vertex is: (-3, -16)

We can see in the graph that the zeros of the function are x=1 and x=-7

Then the function is decreasing from -∞ to -3 and then it is increasing from -3 to ∞

The function is positive for $x$ and $x> 1$

The correct answers are:

Second option

Third option

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3 years ago

Discuss the steps that you used to create your tangent line. What was the most important step?

Otrada [13]

Answer:

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2 years ago

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stellarik [79]

Answer:

-2

Step-by-step explanation:

The slope of a line is rise/run

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7 0

1 year ago

A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he

Nina [5.8K]

The maximum units is 200 and , Total revenue is $8,000

<u>Step-by-step explanation:</u>

Here we have , A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he maximum reveremany should be manufactured to obtain this maximum units .Let's find out:

We have following function as $R(x)=80x-0.2x^ 2$ . Let's differentiate this and equate it to zero to find value of x for which the function is maximum!

⇒ $R(x)=80x-0.2x^ 2$

⇒ $\frac{d(R(x))}{dx}=\frac{d(80x-0.2x^ 2)}{dx}$

⇒ $\frac{d(R(x))}{dx}=\frac{d(80x)}{dx}-\frac{d(0.2x^ 2)}{dx}}$

⇒ $0=80-2x(0.2)$

⇒ $\frac{80}{0.4}=x$

⇒ $x=200$

Now , Value of function at x=200 is :

⇒ $R(200)=80(200)-0.2(200)^ 2$

⇒ $R(200)=16000-8000$

⇒ $R(200)=8000$

Therefore , The maximum units is 200 and , Total revenue is $8,000

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2 years ago