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3 years ago

List any two types of mixtures that are not covered in the Exploration. Also mention the state

Chemistry

1 answer:

marishachu [46]3 years ago

7 0

This question is incomplete because you lack the options. But it can be answered based on my knowledge.

Two types of mixture could be: homogeneous and heterogeneous

A mixture is a term that refers to the combination of two or more components joined but not chemically combined. Mixtures can be classified as follows:

Homogeneous: Are characterized by having a uniform texture and appearance, their components are not distinguished.
For example: water + grapes = wine

Homogeneous mixtures can be:

Solutions: The mixtures formed are characterized by being formed with components that do not react chemically with each other, but that can modify their physical properties when they become part of the solution.
For example: coffee + milk = Coffee

There are also Colloids, a type of mixture formed by particles of one or more substances that are dispersed in another substance called a dispersing medium.

For example Gelatin powder + Water = Gelatin.

They are the intermediate mixtures between homogeneous and heterogeneous.

Heterogeneous: Are mixtures in which it is possible to observe their components due to the discontinuity with the naked eye.
For example Milk + cereal = Cereal

Learn more in: brainly.com/question/24713315

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What do noble gases all have in common?

erastova [34]

Answer:

D. They react readily with oxygen in the air

3 0

2 years ago

An unknown liquid is composed of 34.31% c, 5.28% h, and 60.41% i. The molecular weight is 210.06 amu. What is the molecular form

ozzi

In an unknown liquid, the percentage composition with respect to carbon, hydrogen and iodine is 34.31%, 5.28% and 60.41% respectively.

Let the mass of liquid be 100 g thus, mass of carbon, hydrogen and oxygen will be 34.31 g, 5.28 g and 60.41 g respectively.

To calculate molecular formula of compound, convert mass into number of moles as follows:

$n=\frac{m}{M}$

Molar mass of carbon, hydrogen and iodine is 12 g/mol, 1 g/mol and 126.90 g/mol.

Taking the ratio:

$C:H:I=n_{C}:n_{H}:n_{I}$

Putting the values,

$C:H:I=\frac{34.31 g}{12 g/mol}:\frac{5.28 g}{1 g/mol}:\frac{60.41 g}{126.90 g/mol}=6:11:1$

Thus, molecular formula of compound will be $C_{6}H_{11}I$ .

4 0

3 years ago

What change in volume results if 60.0 mL of gas is cooled from 33.0 °C to 5.00°C?

Mariana [72]

The volume of the gas will be decreased. Answer lies on the understanding of kinetic energy of particles and how particles occupy certain amount of space.
I forgot to add: the answer is 50.91 difference in temperature.

3 0

3 years ago

Consider the reaction: N2(g) + O2(g) ⇄ 2NO(g) Kc = 0.10 at 2000oC Starting with initial concentrations of 0.040 mol/L of N2 and

IrinaVladis [17]

Answer:

0.011 mol/L

Explanation:

This can be solved with something called an ICE table.

I = initial

C = change

E = equilibrium

Initially, there is 0.04 M of N₂, 0.04 M of O₂, and 0 M of NO.

x amount of N₂ reacts. Since the stoichiometry is 1:1, x amount of O₂ also reacts. This produces 2x of NO.

After the reaction, there is 0.04-x of N₂, 0.04-x of O₂, and 2x of NO.

Here it is in table form:

$\left[\begin{array}{cccc}&N2&O2&NO\\I&0.04&0.04&0\\C&-x&-x&+2x\\E&0.04-x&0.04-x&2x\end{array}\right]$

Now we can use the equilibrium constant:

Kc = [NO]² / ( [N₂] [O₂] )

Substituting:

0.10 = (2x)² / ( (0.04 - x) (0.04 - x) )

Solving:

0.10 = (2x)² / (0.04 - x)²

√0.10 = 2x / (0.04 - x)

(√0.10) (0.04 - x) = 2x

(√0.10)(0.04) - (√0.10)x = 2x

(√0.10)(0.04) = 2x + (√0.10)x

(√0.10)(0.04) = (2 + √0.10)x

x = (√0.10)(0.04) / (2 + √0.10)

x = 0.0055

At equilibrium, the concentration of NO is 2x. So the answer is:

[NO] = 2x

[NO] = 0.011

The equilibrium concentration of NO is 0.011 mol/L.

3 0

3 years ago

Which describe beta decay? Check all that apply 1.In beta decay, a proton becomes a neutron and a positron 2.In beta decay, a ne

ivanzaharov [21]

haha thanks again for the help.

3 0

3 years ago

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