Answer:
W = ½ m v²
Explanation:
In this exercise we must solve it in parts, in a first part we use the conservation of the moment to find the speed after the separation
We define the system formed by the two parts of the rocket, therefore the forces during internal separation and the moment are conserved
initial instant. before separation
p₀ = m v
final attempt. after separation
= m /2 0 + m /2 v_{f}
p₀ = p_{f}
m v = m /2 
v_{f}= 2 v
this is the speed of the second part of the ship
now we can use the relation of work and energy, which establishes that the work is initial to the variation of the kinetic energy of the body
initial energy
K₀ = ½ m v²
final energy
= ½ m/2 0 + ½ m/2 v_{f}²
K_{f} = ¼ m (2v)²
K_{f} = m v²
the expression for work is
W = ΔK = K_{f} - K₀
W = m v² - ½ m v²
W = ½ m v²
Yes because as more water leaks in the more water it will displace
Answer:
<h2>5N</h2>
Explanation:
To get the magnitude of the force would require to just loosen the nut, if the force apply perpendicularly at the end of the handle, we will have to resolve the force perpendicular to the wrench. Torque is the turning effect of a body or force about a point. It is similar to moments.
Torque = Force * radius
Note that the force must be perpendicular to the wrench. On resolving the force perpendicularly to the wrench, we will have to resolve the force to the vertical.
Fy = Fsinθ
Fy = 10sin30°
Fy = 10 * 0.5
Fy = 5N
<em>Torque = Fy * r</em>
<em>Given Fy = 5N and r = 20cm = 0.2m</em>
<em>Torque = 5 * 0.2</em>
<em>Torque = 1Nm</em>
<em />
<em>Hence the magnitude of the force would require to just loosen the nut, if the force apply perpendicularly at the end of the handle is 5N</em>
Both F's are forces, so µ must be unitless/dimensionless.
F[friction] = µ F[normal]
Or, more explicitly in terms of the units:
(Newtons) = (constant) (Newtons)
Answer:
r = 0.664 m.
Explanation:
Let's write the equation of the magnetic force, the blacks syndicate vectors
F = q v x B
From this expression we see that the force is perpendicular to the velocity and the field, so it is a centripetal force, the modulus of the force is
F = q v B sinT
We write Newton's second law
F = m a
a = v² / r
q v B sinT = m v² / r
r = m v / (q B sinT)
Let's calculate
r = 9.1 10-31 2.9 107 / (1.6 10-19 1.7 10-3 sin8.4)
r = 26.4 10-24 / 0.3973 10-22
r = 0.664 m
This is the distance from where the electron penetrates
