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bekas [8.4K]
3 years ago
10

Gold has a density of 19.3 g/cm3. What is the mass of a 5 cm3 block of gold?

Physics
1 answer:
Tems11 [23]3 years ago
5 0
Do not forget that mass = <span>volume x density
</span>Mass of 1 cm^3 = Density[/tex]
mass of 2 cm^3 = 19.3 g + 19.3 g = 2*19.3 g
Then eventually we can find <span>mass of 5 cm^3 : = 
</span>19.3 g + 19.3 g+19.3g+19.3g+19.3g= 5*19.3 g
So the answer is D
<span>And that's it. I'm sure it will help.</span>
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A scaffold of mass 57 kg and length 6.5 m is supported in a horizontal position by a vertical cable at each end. A window washer
Mrac [35]

Explanation:

The given data is as follows.

     m_{1} = 57 kg,        m_{2} = 79 kg

      l_{1} = 6.5 m,         l_{2} = (6.5 - 1.9) m = 4.6 m

(a)  The sum of torque ends about far end is as follows.

    m_{1}g \frac{l_{1}}{2} + m_{2}g \times l_{2} - T \times l_{1} = 0

     57 \times 9.81 \times \frac{6.5}{2} + 79 \times 9.81 \times (6.5 - 1.9) - T \times 6.5 = 0

                     T = 828 N

Therefore, 828 N is the tension in the cable closer to the painter.

(b)  Now, we will calculate the sum about close ends as follows.

m_{1}g \frac{l_{1}}{2} + m_{2}g \times (1.9) - T \times l_{1}    

  57 \times 9.81 \times \frac{6.5}{2} + 79 \times 9.81 \times (1.9) - T \times 6.5 = 0

                            T= 506 N

Therefore, 506 N is the tension in the cable further from the painter.  

8 0
3 years ago
During physical activity of moderate intensity, your heart will beat at a percentage of its maximum rate. What is the target hea
Phoenix [80]
The target heart rate for moderate-intensity activity is 80%
8 0
3 years ago
In an experiment conducted using the Young's double-slit apparatus, the separation between the slits is 20 µm. A first-order con
jeka57 [31]
To solve this problem, we use the formula
λ = s sin θ
where s is the separation and θ is the angle interference
So,
λ = 20 x 10^-6 sin 2.5
λ = 8.72 x 10^-7 m

The required angle for the fourth order bright fringe is
θb = sin⁻¹ (4λ / s) = sin⁻¹ (4 (8.72 x 10^-7 m)/ 20 x 10^-6 ) = 10.04°

The required angle for the fourth order dark fringe is
θd = sin⁻¹ (4.5 λ / s) = sin⁻¹ (4.5 (8.72 x 10^-7 m)/ 20 x 10^-6 ) = 11.31°
6 0
3 years ago
g Describe how an electron can possess the properties of both a particle and a wave. How do the wave properties of electrons rel
nalin [4]

Answer:

See explanation

Explanation:

According to Louis de Broglie, matter has an associated wavelength. Hence, there exist no clear cut difference between matter and wave. Matter may be regarded as a wave and vice versa depending on the behavior of each under the given circumstances.

According to Heisenberg uncertainty principle, the position and momentum of matter can not be simultaneously determined with precision. This further reinforces the wave-particle concept of the electron.

When electrons are passed through crystals, they are diffracted just like electromagnetic waves. This further reinforces the wave-particle paradox.

According to The Heisenberg uncertainty principle, the wave property of electrons determine their exact location in space

8 0
3 years ago
What is the kinetic energy of a 1500 kg object moving at a velocity of 10 m/s?
Anastasy [175]
The Kinetic Energy Formula is as follows: KE = mass x velocity^2 /2

Plug in the correct numbers into the variables!

KE = 1500 kg x 10 m/s ^2 / 2

Square the 10 m/s!

KE = 1500 kg x 100 m/s / 2

Multiply!

KE = 150,000 / 2

Divide!

KE = 75,000 Newton-meters or Joules!


4 0
3 years ago
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