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3 years ago

Gold has a density of 19.3 g/cm3. What is the mass of a 5 cm3 block of gold?

1 answer:

5 0

Do not forget that mass = volume x density
Mass of 1 cm^3 = Density[/tex]
$mass of 2 cm^3 = 19.3 g + 19.3 g = 2*19.3 g$
Then eventually we can find mass of 5 cm^3 : =
 $19.3 g + 19.3 g+19.3g+19.3g+19.3g= 5*19.3 g$
So the answer is D
And that's it. I'm sure it will help.

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Under which circumstances would protesters’ right to assembly most likely be protected?

ICE Princess25 [194]

Answer:

Explanation:

Mob violence is never protected. Organizers are always careful about not letting things get out of hand. Not D

That remark sort of applies to C as well. Property destruction is never protected.

B is something assemblies are allowed to do. So B.

A falls into the same category as C and D. You may not like the fact that he/she is doing something illegal, but you can't take away their privacy.

7 0

2 years ago

An object of mass 10.0kg is released at point A, slidesto the bottom of the 30° incline, then collides with ahorizontal massless

Elenna [48]

Answer:

Explanation:

Potential energy lost by mass = mgh

= 10 x 9.8 x 2 = 196 J

a ) If v be velocity of mass at the bottom , its kinetic energy will be stored in spring as elastic energy

= 1/2 m v² = 1/2 k x² , k is spring constant , x is compression , m is mass falling down

.5 x 10 v² = .5 x 500 x .75²

v = 5.3 m /s

b ) kinetic energy of mass at the bottom

= /2 m v²

= .5 x 10 x 5.3²

= 140.45 J

energy lost by mass while coming down

=potential energy at the top - kinetic energy at bottom

= 196 - 140.45

= 55.55 J .

This is equal to negative work done by friction

work done by friction = - 55.55 J

c ) Since there will be no loss of energy in compression and extension of spring so , no loss of kinetic energy will take place of mass . So it wil have same velocity that is 5.3 m /s while on its return journey.

d ) kinetic energy at the bottom = 140.45

loss of energy by friction again

= 140.45 - 55.55

= 84.9 J

If h be the height attained

mgh = 84.9

10 x 9.8 x h = 84.9

h = .866 m

( We have assumed that loss of energy in return journey will be same due to friction . )

6 0

3 years ago

Azurite is a mineral that contains 55.1% of copper. How many meter of copper wire with diameter of 0.0113 in can be produced fro

soldier1979 [14.2K]

Answer:

1402.73 m

Explanation:

Mass of Azurite=3.25 lb

Percent of copper in AZurite mineral=55.1%

Diameter of copper wire,d=0.0113 in

Radius of copper wire= $r=\frac{d}{2}=\frac{0.0113}{2}=0.00565 in=\frac{565}{100000}=\frac{565}{100}\times \frac{1}{1000}=5.65\times 10^{-3}in$

$\frac{1}{1000}=10^{-3}$

Density of copper= $\rho=8.96g/cm^3$

1 lb=454 g

3.25 lb= $3.25\times 454=1475.5 g$

Mass of Azurite= $1475.5 g$

Mass of copper= $\frac{55.1}{100}\times 1475.5=813 g$

Density= $\frac{Mass}{volume}$

Using the formula

$8.96=\frac{813}{volume\;of\;copper}$

Volume of copper wire= $\frac{813}{8.96}=90.7cm^3$

Radius of copper wire= $5.65\times 10^{-3}\times 2.54=14.35\times 10^{-3} cm$

1 in=2.54 cm

Volume of copper wire= $\pi r^2 h$

$\pi=3.14$

Using the formula

$90.7=3.14\times (14.35\times 10^{-3})^2\times h$

$h=\frac{90.7}{3.14\times (14.35\times 10^{-3})^2}$

$h=140273 cm$

1 m=100 cm

$h=\frac{140273}{100}=1402.73 m$

Hence, the length of copper wire required=1402.73 m

7 0

3 years ago

A runner goes around a 1 mile track if they end up at their starting position what is their dosplacement

mario62 [17]

Answer:

The displacement is zero

Explanation:

Displacement is a vector that connects the starting position of motion of an object to the final position. It is a vector quantity, so it has both magnitude and direction.

Viceversa, distance is a scalar quantity that measures the total length of the path covered by the object during its motion.

In this problem, we are interested in the displacement.

We are told that the runner goes around a 1 mile track, and he ends at his starting position: this means that his final position is equal to the starting position, therefore the displacement is zero.

8 0

3 years ago

Refraction occurs because of changes in the _____________

IrinaVladis [17]

Speed of the beam as it passes from one transparent medium to another

3 0

2 years ago