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Gnesinka [82]
3 years ago
6

The nearest star to our planet other than the sun , is 4.4 light year away.One light-year is the distance light travels in a yea

r.
* HOW LONG DOES IT TAKE FOR TO REACH US?
* SUGGEST WHY LIGHT-YEAR IS USED AS THE UNIT FOR MEASURING THE DISTANCE BETWEEN DISTANT STARS AND OUR PLANET, RATHER THAN THE UNIT 'KILOMETER,
Physics
1 answer:
lozanna [386]3 years ago
3 0

Answer:

1606

The main reason for using light years, however, is because the distances we deal with in space are immense. If we stick to miles or kilometers we quickly run into unwieldy numbers just measuring the distance to the nearest star: a dim red dwarf called Proxima Centauri that sits a mere 24,000,000,000,000 miles away!

Explanation:

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while driving his sports car at 20.0 m/s down a four lane highway, eddie comes up behind a slow moving dump truck and decides to
Arte-miy333 [17]

Explanation:

Given:

u = 20 m/s

a = 5 m/s^2

v = 30 m/s

t = ?

Use the first kinematic equation of motion:

v = u + at

t = (v - u)/a = 10/5 = 2 seconds

3 0
2 years ago
An object of mass m is traveling on a horizontal surface. There is a coefficient of kinetic friction  between the object and th
Gnom [1K]

Answer:

8m * (μg/v)^2

Explanation:

k, the spring constant = ?

(k in terms of μ, m, g, and v.)

Frictional force = μmg

Note: lost KE is converted to work done against the friction + PE of the spring

1/2mv2 = μmgx + 1/2kx^2....equation i

Cancel the 1/2 on both sides

mv^2 = μmgx + kx^2

Lets recall that:

Due to frictional effect, further enegy will be lost when the spring recoils backward

Therefore

1/2kx^2 = μmgx..... equation ii

Let's substitute 1/2kx^2 in equation I for ii

So we can say that:

1/2mv^2 = (μmgx)+ μmgx

1/2mv^2 = 2 (μmgx)

1/4mv^2 = μmgx

Cancel out m on both sides

1/4v^2 = μgx

Make x subject of the formula

x = (1/4v^2) / (μg)...... equation iii

substitute x to equation ii

But first make k in equation ii subject of the formula

1/2kx^2 = μmgx

k = 2μmg/x

Now substitute x

k = 2μmg / ((1/4v^2) / (μg))

k = 2μmg * ((μg) / (1/4v^2))

k = 8m * (μg/v)^2

8m * (μg/v)^2

7 0
2 years ago
Which of the following types of technologies has best helped scientists to study very high-energy objects in outer space, such a
erica [24]

Very high-energy objects and events spit out very high-energy photons, so the instrument you need in order to detect them is the       X-ray telescope. <em>(C)  </em>

Inconveniently, X-ray telescopes only work when they're up in orbit, because X-rays get seriously soaked up in Earth's atmosphere, and most of them never make it down to the surface ... (lucky for us !) .

3 0
3 years ago
Read 2 more answers
A projectile is fired vertically from Earth's surface with
scoray [572]

Answer:

h=25.52\times10^6 m

Explanation:

Initial speed, v = 10 x 10^3 m/s

Mass of the earth, M = 6 x 10^24 kg

Radius of the earth, R = 6.4 x 10^6 m

Maximum from the surface of earth, h = ?

Let  m = Mass of the projectile

Solution:

Potential energy at maximum height =  ( Potential + Kinetic energy ) at the surface

-G M m / ( R + h )=- G M m / R + (1/2) m v^2

- G M / ( R + h ) = - G M / R + (1/2) v^2

-2\times G M / ( R + h ) = ( - 2 G M / R ) + v^2

-2\times6.67\times10^{-11}\times6\times10^{24}/ ( R + h )

=( (- 2\times 6.67\times10^{-11}\times6\times10^{24}) /(6.4\times10^6)} +10000^2

=-2.50625\times10^7 J

=- 8\times10^{14} / ( R + h )=-2.50625\times 10^7

R+h=31.92\times10^{6}

h=31.92\times10^{6}-6.4\times10^6

h=25.52\times10^6 m

5 0
2 years ago
At speeds over 30 mph, you should maintain a following distance of at least ________ behind the vehicle ahead of you.
ICE Princess25 [194]

At speeds over 30 mph, you should maintain a following distance of at least <u>three full seconds</u> behind the vehicle ahead of you.

As a general rule and common sense at a speed of 30 mph you can leave three full seconds so that you can achieve a prudent distance between the car you are driving and the car in front in order to be able to perform some kind of maneuver if an accident or unforeseen event occurs.

To count the full three seconds you can use the technique of counting the Mississippis as follows: Mississippi one, Mississippi two, Mississippi three.

<h3>What is an accident?</h3>

An accident is an unexpected event that generally causes damage, injury or negative consequences.

Learn more about accident at: brainly.com/question/28070413

#SPJ4

7 0
1 year ago
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