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statuscvo [17]
3 years ago
8

PELASEE HELPPP WITH MARK BRAINLIST!!!! You are stopped at a red light, and a long string of cars is crossing in front of you. Wh

en their traffic light turns red and yours turns green, the crossing traffic continues to enter the intersection. You should
Remain stopped until all the crossing traffic has crossed through the intersection.

Call the police on your cell phone to report them.

Move forward while honking your horn, to force the crossing traffic to obey the traffic signal.
Engineering
2 answers:
choli [55]3 years ago
7 0

Answer:

1st one.

Explanation:

I think that because they the one who is going to get a ticket and also you will not gonna get in a car accident.

Tpy6a [65]3 years ago
3 0

Answer:

Hello there the Correct answer is A.

Because it shows that you can GO, but you must first let any vehicles, bicycles, or pedestrians remaining in the intersection get through before you move ahead. You can turn left ONLY if you have enough space to complete the turn before any oncoming vehicle, bicycle, or pedestrian becomes a hazard.

You might be interested in
Socket Programming: (30 points) Use Python TCP socket to implement an application with client-server architecture. In this appli
ololo11 [35]

Answer:

Explanation:

Run the code given in text file following instructions.

Download txt
8 0
3 years ago
g Let the charges start infinitely far away and infinitely far apart. They are placed at (6 cm, 0) and (0, 3 cm), respectively,
irina1246 [14]

Answer:

a) V =10¹¹*(1.5q₁ + 3q₂)

b) U = 1.34*10¹¹q₁q₂

Explanation:

Given

x₁ = 6 cm

y₁ = 0 cm

x₂ = 0 cm

y₂ = 3 cm

q₁ = unknown value in Coulomb

q₂ = unknown value in Coulomb

A) V₁ = Kq₁/r₁

where   r₁ = √((6-0)²+(0-0)²)cm = 6 cm = 0.06 m

V₁ = 9*10⁹q₁/(0.06) = 1.5*10¹¹q₁

V₂ = Kq₂/r₂

where   r₂ = √((0-0)²+(3-0)²)cm = 3 cm = 0.03 m

V₂ = 9*10⁹q₂/(0.03) = 3*10¹¹q₂

The electric potential due to the two charges at the origin is

V = ∑Vi = V₁ + V₂ = 1.5*10¹¹q₁ + 3*10¹¹q₂ = 10¹¹*(1.5q₁ + 3q₂)

B) The electric potential energy associated with the system, relative to their infinite initial positions, can be obtained as follows

U = Kq₁q₂/r₁₂

where

r₁₂ = √((0-6)²+(3-0)²)cm = √45 cm = 3√5 cm = (3√5/100) m

then

U = 9*10⁹q₁q₂/(3√5/100)

⇒ U = 1.34*10¹¹q₁q₂

5 0
2 years ago
In C++ the declaration of floating point variables starts with the type name float or double, followed by the name of the variab
zubka84 [21]

Answer:

The given grammar is :

S = T V ;

V = C X

X = , V | ε

T = float | double

C = z | w

1.

Nullable variables are the variables which generate ε ( epsilon ) after one or more steps.

From the given grammar,

Nullable variable is X as it generates ε ( epsilon ) in the production rule : X -> ε.

No other variables generate variable X or ε.

So, only variable X is nullable.

2.

First of nullable variable X is First (X ) = , and ε (epsilon).

L.H.S.

The first of other varibles are :

First (S) = {float, double }

First (T) = {float, double }

First (V) = {z, w}

First (C) = {z, w}

R.H.S.

First (T V ; ) = {float, double }

First ( C X ) = {z, w}

First (, V) = ,

First ( ε ) = ε

First (float) = float

First (double) = double

First (z) = z

First (w) = w

3.

Follow of nullable variable X is Follow (V).

Follow (S) = $

Follow (T) = {z, w}

Follow (V) = ;

Follow (X) = Follow (V) = ;

Follow (C) = , and ;

Explanation:

4 0
3 years ago
1. Two technicians are discussing tire rotation. Technician A says that you always follow the tire-rotation procedure outlined i
siniylev [52]

Answer:

don't know

Explanation:

huhuh

8 0
3 years ago
Calculate the pressure drop in a duct (measured by a differential oil manometer) if the differential height between the two flui
Burka [1]

Answer:

The pressure drop is 269.7N/m^2

Explanation:

∆P = ∆h × rho × g

∆h = 3.2cm = 3.2/100 = 0.032m, rho = 860kg/m^3, g = 9.8m/s^2

∆P = 0.032×860×9.8 = 269.7N/m^2

6 0
3 years ago
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