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Romashka-Z-Leto [24]
3 years ago
10

a) Give a brief description of the type of DC motor that operates with its field windings running in Series with the armature an

d list two (2) of its features.
Engineering
1 answer:
astraxan [27]3 years ago
5 0

Answer:

The answer to the question is:

Explanation:

The series motor or series excitation motors, is a type of direct current electric motor in which the armature and the inductor or excitation winding are connected in series. The applied voltage is constant, while the excitation field increases with the load, since the current is the same excitation current. The flow increases in proportion to the current in the armor, as the flow grows with the load, the velocity drops as that load increases.

The main features of this engine are:

- It is packed when it is idle, because the speed of a direct current motor increases as the inductor flow decreases and, in the series motor, this decreases with increasing speed, since the intensity in the inductor is the same as in the induced.

- The power is almost constant at any speed.

- The abrupt variations in the supply voltage affect it little, since an increase in this causes an increase in the intensity and, therefore, in the flow and the counter-electromotive force, stabilizing the absorbed intensity.

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Answer:

A benchmark

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Most times a benchmark serves as the better measure when assessing a computer's performance, this is because CPU speeds can only evaluate an aspect of a computer's performance whereas a benchmark offers the advantage of measuring all the aspects of a computer's performance for a specific type of computing problem.

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The pressure of a gas in a rigid container is 125kpa at 300k, what we be the new pressure if the temperature increases to 900k​
kipiarov [429]

Answer:

375 KPa

Explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 125 KPa

Initial temperature (T₁) = 300 K

Final temperature (T₂) = 900 K

Final pressure (P₂) =?

The new (i.e final) pressure of the gas can be obtained as follow:

P₁/T₁ = P₂/T₂

125 / 300 = P₂ / 900

Cross multiply

300 × P₂ = 125 × 900

300 × P₂ = 112500

Divide both side by 300

P₂ = 112500 / 300

P₂ = 375 KPa

Thus, the new pressure of the gas is 375 KPa

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