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Marta_Voda [28]
4 years ago
7

Create a Python program that will produce the following output:

Engineering
1 answer:
Aloiza [94]4 years ago
6 0

Answer:

def main ():

   sentence = input("Please enter a sentence:")

   print("Original Sentence:",sentence)

   # start at the third character

   for i in range(2,  len(sentence), 3):

       # access the string by index  

       print("Every third letter:", sentence[i])

Explanation:

def helps define the sentence ( input)

in order to start printing from third letter we start the range from 2 and keep the step 3 . The range i is in square parenthesis to show the range and access string.

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Please help me with this question
Nat2105 [25]

Answer:

The answer is c and the teacher helped me

Explanation:

i had help from the tescger and the assignment is done

5 0
2 years ago
Technician A says independent shops are not affiliated with vehicle manufacturers, but it is easy for technicians who work in th
KatRina [158]

Answer:

b

Explanation:

i did it yeater dayajsbs

8 0
3 years ago
the AADT for a section of suburban freeway is 150000 veh/day. Assuming this is an urban radial facility, what range of direction
igomit [66]

Answer:

design hour volumes will be 4000 to 6000

Explanation:

given data

AADT  = 150000 veh/day

solution

we get here design hour volumes that is express as

design hour volumes  = AADT × k × D    ..............1

here k is factor and its  range is 8 to 12 % for urban

and D is directional distribution i.e traffic equal divided by the direction

so here design hour volumes will be 4000 to 6000

7 0
3 years ago
In the circuit given below, R1 = 17 kΩ, R2 = 74 kΩ, and R3 = 5 MΩ. Calculate the gain 1formula58.mml when the switch is in posit
Elenna [48]

Answer:a

a) Vo/Vi = - 3.4

b) Vo/Vi = - 14.8

c) Vo/Vi = - 1000

Explanation:

a)

R1 = 17kΩ

for ideal op-amp

Va≈Vb=0 so Va=0

(Va - Vi)/5kΩ + (Va -Vo)/17kΩ = 0

sin we know Va≈Vb=0

so

-Vi/5kΩ + -Vo/17kΩ = 0

Vo/Vi = - 17k/5k

Vo/Vi = -3.4

║Vo/Vi ║ = 3.4    ( negative sign phase inversion)

b)

R2 = 74kΩ

for ideal op-amp

Va≈Vb=0 so Va=0

so

(Va-Vi)/5kΩ + (Va-Vo)74kΩ = 0

-Vi/5kΩ + -Vo/74kΩ = 0

Vo/Vi = - 74kΩ/5kΩ

Vo/Vi = - 14.8

║Vo/Vi ║ = 14.8  ( negative sign phase inversion)

c)

Also for ideal op-amp

Va≈Vb=0 so Va=0

Now for position 3 we apply nodal analysis we got at position 1

(Va - Vi)/5kΩ + (Va - Vo)/5000kΩ = 0           ( 5MΩ = 5000kΩ )

so

-Vi/5kΩ + -Vo/5000kΩ = 0

Vo/Vi = - 5000kΩ/5kΩ

Vo/Vi = - 1000

║Vo/Vi ║ = 1000  ( negative sign phase inversion)

3 0
3 years ago
A pinion and gear pair is used to transmit a power of 5000 W. The teeth numbers of pinion
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