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AveGali [126]
2 years ago
14

How does manufacturing affect the economy and society?

Engineering
2 answers:
ratelena [41]2 years ago
6 0

Explanation:

Because manufacturing has so many substantial links with so many other sectors throughout the economy, its output stimulates more economic activity across society than any other sector. That's a major reason manufacturers play such a critical role in growth.

mr Goodwill [35]2 years ago
3 0

Answer:

Manufacturing helps raise living standards more than any other sector. Manufacturing generates more economic activity than other sectors. For every dollar of domestic manufacturing value-added, another $3.60 of economic activity is generated elsewhere across the economy.

hope this helped

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Four kilograms of carbon monoxide (CO) is contained in a rigid tank with a volume of 1 m3. The tank is fitted with a paddle whee
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Answer:

a) 1 m^3/Kg  

b) 504 kJ

c) 514 kJ

Explanation:

<u>Given  </u>

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-The time of adding energy t = 10 s  

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ΔPE =0  

<u>Required  </u>

(a)Specific volume at the final state v_2

(b)The energy transferred by the work W in kJ.  

(c)The energy transferred by the heat transfer W in kJ and the direction of  

the heat transfer.  

Assumption  

-Quasi-equilibrium process.  

<u>Solution</u>  

(a) The volume and the mass doesn't change then, the specific volume is constant.

 v= V_tank/m ---> 1/1= 1 m^3/Kg  

(b) The added work is defined by.  

W =E * t --->  14 x 10 x 3600 x 10^-3 = 504 kJ  

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Q - W = m * Δu

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The heat have (+) sign the n it is added to the system.

7 0
2 years ago
A water supply agency is planning to add two reservoirs to its system. Water will flow from Reservoir A to Reservoir B via a 10,
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Attached is the solution to the above question.

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The fracture toughness of a stainless steel is 137 MPa*m12. What is the tensile impact load sustainable before fracture that a r
Charra [1.4K]

Answer:

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Explanation:

The capacity of a material having a crack to withstand fracture is referred to as fracture toughness.

It can be expressed by using the formula:

K = \sigma Y \sqrt{\pi a}

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fracture toughness K = 137 MPam^{1/2}

geometry factor Y = 1

applied stress \sigma = ???

crack length a = 2mm = 0.002

∴

137 =\sigma \times 1  \sqrt{ \pi \times 0.002 }

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7 0
3 years ago
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