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Mrac [35]
2 years ago
10

Sage has 3 strip-mats, 3 mats, and 2 units. Tristan has 2 mats, 8 strips, and 5 units. Andre had twice as many strip-mats, mats,

and units as Sage. How many units is that in all? show your work.​
Mathematics
1 answer:
sladkih [1.3K]2 years ago
7 0

The question is an illustration of equivalent equations.

<em>There are 11 units in all</em>

The given parameters are:

<u>Sage</u>

\mathbf{Strip-mat = 3}

\mathbf{Mat = 3}

\mathbf{Units = 2}

<u>Tristan</u>

\mathbf{Strip-mat = 8}

\mathbf{Mat = 2}

\mathbf{Units = 5}

Andre has twice of what Sage has

So, the total unit is:

\mathbf{Total = Sage + Tristan + Andre}

<em>Sage has 2 units</em>

<em>Tristan has 5 units</em>

<em />

Because, Andre has twice of what <em>Sage has,</em>

Andre's number of units would be 4

So, we have:

\mathbf{Total = 2 +5 + 4}

\mathbf{Total = 11}

Hence, there are 11 units in all

Read more about equivalent equations at:

brainly.com/question/18720297

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