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2 years ago

Which group will have an electron configuration that ends in s2?

Chemistry

1 answer:

Step2247 [10]2 years ago

8 0

<h2>Answer: c . Alkaline earth metals (Group 2)</h2>

<h3>Explanation:</h3>

Group 2 metals have 2 electrons in their outer shell. These two electrons are usually found in the s orbital, hence the s².

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Which redox reaction would most likely occur if zinc and copper metal were

sweet-ann [11.9K]

Answer:

Explanation:

b/c when copper and zinc metal are addedto solution,then the solution will be consider under redox reaction

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3 years ago

If an object has a mass of 180 g and a density of 6 g/cm^3, what is the volume of the object?

cupoosta [38]

Answer:

<h3>The answer is 30 cm³</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question

mass = 180 g

density = 6 g/cm³

We have

$volume = \frac{180}{6} \\$

We have the final answer as

Hope this helps you

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3 years ago

All the elements of a family in the periodic table have what feature in common?

SCORPION-xisa [38]

They all have the same number of electrons in the electron cloud.

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3 years ago

Read 2 more answers

Calculate the mass of 12.044*10^23atom of carbon

Keith_Richards [23]

Answer: 24 gram is a final Answer.

Explanation:1 mol of carbon weight is 12 gram then

12.044×1023 contain 2 mole carbon so

4 0

3 years ago

2HgCl2(aq) + C2O42–(aq) → 2Cl–(aq) +2CO2(g) + Hg2Cl2(s)

alexgriva [62]

Explanation:

Expression for rate of the given reaction is as follows.

Rate = k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y[/tex]

Therefore, the reaction equations by putting the given values will be as follows.

$1.8 \times 10^{-5} = k[0.105]x [0.15]y$ ............. (1)

$7.2 \times 10^{-5} = k [0.105]x [0.30]y$ ........... (2)

$3.6 \times 10^{-5} = k [0.0525]x [0.30]y$ ............ (3)

Now, solving equations (1) and (2) we get the value of y = 2. Therefore, by solving equation (2) and (3) we get the value of x = 1.

Therefore, expression for rate of the reaction is as follows.

Rate = $k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y$

Rate = $k [HgCl2]1 [C_{2}O^{-2}_{4}]2$

Hence, total order = 1 + 2 = 3

According to equation (1),

$1.8 \times 10^{-5} = k[0.105]x [0.15]y$

$1.8 \times 10^{-5} = k [0.105]1 [0.15]2$

k = $7.6 \times 10^{-3} M^{-2} min^{-1}$

Thus, we can conclude that rate constant for the given reaction is $7.6 \times 10^{-3} M^{-2} min^{-1}$ .

8 0

2 years ago