Mass of object/source
Gravity
Fg=mg
The distance between slit and the screen is 1.214m.
To find the answer, we have to know about the width of the central maximum.
<h3>How to find the distance between slit and the screen?</h3>
- It is given that, wavelength 560 nm passes through a slit of width 0. 170 mm, and the width of the central maximum on a screen is 8. 00 mm.
- We have the expression for slit width w as,

where, d is the distance between slit and the screen, and a is the slit width.
- Thus, distance between slit and the screen is,

Thus, we can conclude that, the distance between slit and the screen is 1.214m.
Learn more about the width of the central maximum here:
brainly.com/question/13088191
#SPJ4
Explanation:
If we assume negligible air resistance and heat loss, we can assume that all of the Gravitational potential energy of the ball will turn into Kinetic energy as it falls toward the ground.
Therefore our Kinetic energy = mgh = (10kg)(9.81N/kg)(100m) = 9,810J.
Answer:
Input force of pulley system = 200 N
Explanation:
Given:
Mechanical advantage of pulley system = 5
Output force from pulley system = 1,000 N
Find;
Input force of pulley system
Computation:
Mechanical advantage = Output force / Input force
Mechanical advantage of pulley system = Output force from pulley system / Input force of pulley system
5 = 1,000 / Input force of pulley system
Input force of pulley system = 1,000 / 5
Input force of pulley system = 200 N
Answer: friction reduces the speed during motion
Explanation:
The more the friction, the lesser the speed during motion