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deff fn [24]
3 years ago
6

50 points and brainliest!!!! plz help me

Physics
2 answers:
antoniya [11.8K]3 years ago
3 0

decrease yeah free 100 percent

disa [49]3 years ago
3 0

Answer:

The amount of gas molecules in the air decreaces while traveling up through the troposphere—the air becomes less dense than air nearer to sea level.

Explanation:

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Formula for the distance (d) is given by d = rate*time. For example if you are traveling at 60 mph for 3 hours the distance trav
babunello [35]

Explanation:

Distance covered by the particle is given by:

Distance (d) = rate (v) × time (t)                

Speed of Mary, v₁ = 50 mph

Speed of Jim, v₂ = 60 mph

It is assumed that, Mary and Jim leave at the same time. After one hour, Jim is 10 miles ahead.

Distance travelled by Jim, d₁ = (60t + 10)

Distance travelled by Mary, d₂ = 50t

The distance between Mary and Jim is greater than or equal to 100 miles.

60t+10-50t\ge100

10t\ge90

t\ge9\ h

So, Jim takes is 9 hours more than Mary to cover same distance. Hence, this is the required solution.

7 0
3 years ago
The diagram is being used to illustrate the second law of thermodynamics, where Qh represents a hot object and Qc represents a c
katrin [286]

Answer:

The answer is A. on edgen.

Explanation:

A. adding in the boxes an arrow that points from Qh to Qc

6 0
3 years ago
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An electric motor draws out 5 A of current from a 20 V battery. How much power is it using?
irinina [24]

Answer:

Explanation:

P = VI = 20(5) = 100 W

7 0
3 years ago
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Help with 3 please! I will give brainliest!
rusak2 [61]
The answer is point b because vertical velocity is zero at the maximum height
8 0
3 years ago
(a) Calculate the acceleration due to gravity on the surface of the Sun.
Ira Lisetskai [31]
<h2>a)Acceleration due to gravity on the surface of the Sun is 274.21 m/s²</h2><h2>b) Factor of increase in weight is 27.95</h2>

Explanation:

a) Acceleration due to gravity

                      g=\frac{GM}{r^2}

 Here we need to find acceleration due to gravity of Sun,

                G = 6.67259 x 10⁻¹¹ N m²/kg²

    Mass of sun, M = 1.989 × 10³⁰ kg

    Radius of sun, r = 6.957 x 10⁸ m

Substituting,

                g=\frac{6.67259\times 10^{-11}\times 1.989\times 10^{30}}{(6.957\times 10^8)^2}\\\\g=274.21m/s^2

Acceleration due to gravity on the surface of the Sun = 274.21 m/s²

b) Acceleration due to gravity in earth = 9.81 m/s²

   Ratio of gravity = 274.21/9.81 = 27.95

   Weight = mg

  Factor of increase in weight = 27.95

8 0
3 years ago
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