Answer:

Therefore, the first choice is correct.
The graph of the inequality is also attached below.
Step-by-step explanation:
Considering the inequality

solving










In other words,

Therefore, the first choice is correct.
The graph of the inequality is also attached below.
Answer:
$936.32
Step-by-step explanation:
To solve this problem we need to find the remaining 12% of money our neighbor has saved since 88% was $836. To do this, we simply multiply $836 by 12%. Remember to change 12% into its decimal form (12% -> 0.12).
$836 x 0.12 = $100.32
Now, our last step is to add $100.32 to $836.
$836 + $100.32 = $936.32
Our answer is $936.32.
X = height of bush
12/3.5 = 3.2/x [cross multiply]
(12)(x) = (3.2)(3.5)
12x = 11.2 [Divide 12 on both sides]
x = 0.93 m
The height of the bush is 0.93 meters.
Best of luck.
Answer:
8x +5
Step-by-step explanation:
that's what I got.................
Answer:
Step-by-step explanation:
Given that,
Cells are divided into two cell every 20mins, this implies that the half-life is 20mins
Initial population growth is 60cells
Growth rate r?
Population growth is modeled as
P(t) = Po•exp(rt)
Where,
Po is the initial growth at t= 0
Po= 60
P(t) is population at any time t.
Since the population doubles every 20mins(⅓hr)
Then, P(⅓) = 2×60 =120
Then, P(t) = 120cells
So, applying the formula
P(t) = Po•exp(rt)
120 = 60•exp(⅓r)
120/60 = exp(r/3)
2 = exp(r/3)
Take In of both sides
In(2) = r/3
Cross multiply
r = 3In(2)
r = 2.079 /hour
The growth rate is 2.079/hour.