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3 years ago

Mx-2mx+my + 2ny I have to factorize this

Mathematics

1 answer:

weqwewe [10]3 years ago

6 0

Answer:

mx(1 - 2) + y(m + 2n)

Step-by-step explanation:

mx - 2mx + my + 2ny

mx(1 - 2) + y(m + 2n)

Hope it helps.

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15/4 divided by -5/8 equals?

kolezko [41]

Answer:

-6

Step-by-step explanation:

15/4 ÷ -5/8

Copy dot flip

15/4 * -8/5

Rewrite

15/5 * -8/4

3 * -2

-6

5 0

3 years ago

Read 2 more answers

Fine the volume please

vaieri [72.5K]

Answer:

212 m²

Step-by-step explanation:

4 x 4 x 5 = 80

6+6+50+30+40

6 0

3 years ago

ANSWER SUPER QUICK

faltersainse [42]

Answer: The required equation is $x=(7\times12-34.5)\div8\frac{1}{4}$

Maria can cut 6 sections from the remaining rope.

Step-by-step explanation:

The total length of rope = 7 feet

since 1 feet = 12 inches

Therefore, 7 feet= $7\times 12=84\ inches$

Let x be the number of sections.

Since the instructions are to use 34.5 inches of rope to tie a tarp on top the the tent. Then, the remaining rope should be cut 8 1/4 inch sections to tie tent to stakes in the ground.

then the required equation will be

$x=(7\times12-34.5)\div8\frac{1}{4}\\\Rightarrow\ x=(84-34.5)\div \frac{33}{4}\\\Rightarrow\ x=49.5\div8.25\\\Rightarrow\ x=6$

So, maria can cut 6 sections.

3 0

3 years ago

find the perimeter of ABC with verticles A(-1,2) B(3,-2) and C(-1,-2). round answer to nearest hundredth

nata0808 [166]

Answer:

A po

Step-by-step explanation:

sana makatulong haaha

5 0

3 years ago

Find the solutions to x⁴-5x²-36=0 and the x-intercepts of the graph of y=x⁴-5x²-36.

disa [49]

Answer:

The solutions $x^4-5x^2-36=0$ are $x=3,\:x=-3,\:x=2i,\:x=-2i$ and the x-intercepts of $y=x^4-5x^2-36$ are $x=3,\:x=-3$

Step-by-step explanation:

Finding the solutions to $x^4-5x^2-36$ means finding the roots, a root is where the function is equal to zero.

The x-intercept is the point at which the graph crosses the x-axis. At this point, the y-coordinate is zero.

To find the roots you need to:

Rewrite the equation with $u=x^2$ and $u^2=x^4$

$u^2-5u-36=0$

Solve by factoring

$\mathrm{Break\:the\:expression\:into\:groups}\\u^2-5u-36=\left(u^2+4u\right)+\left(-9u-36\right)$

$\mathrm{Factor\:out\:}u\mathrm{\:from\:}u^2+4u=u\left(u+4\right)$

$\mathrm{Factor\:out\:}-9\mathrm{\:from\:}-9u-36=-9\left(u+4\right)$

$u^2-5u-36=u\left(u+4\right)-9\left(u+4\right)$

$\mathrm{Factor\:out\:common\:term\:}u+4\\\left(u+4\right)\left(u-9\right)$

$u^2-5u-36=\left(u+4\right)\left(u-9\right)=0$

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions to the quadratic equation are:

$\:u=-4,\:u=9$

Substitute back $u=x^2$ , solve for x

$x^4-5x^2-36=(u-9)(u+4)=(x^2-9)(x^2+4)$

Apply the difference of squares formula

$x^4-5x^2-36=(x^2-9)(x^2+4)=(x-3)(x+3)(x^2+4)$

$(x-3)(x+3)(x^2+4)=0$

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions are:

$\:x=3,\:x=-3,\:x=2i,\:x=-2i$

Because two of the solutions are complex roots the only x-intercepts are $x=3,\:x=-3$

3 0

3 years ago