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3 years ago

Mx-2mx+my + 2ny I have to factorize this

Mathematics

1 answer:

weqwewe [10]3 years ago

6 0

Answer:

mx(1 - 2) + y(m + 2n)

Step-by-step explanation:

mx - 2mx + my + 2ny

mx(1 - 2) + y(m + 2n)

Hope it helps.

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Which equation represents the line that passes through the points (6, -3) and (-4, -9)?

Liula [17]

(6,-3)(-4,-9)
slope = (-9 - (-3) / (-4 - 6) = (-9 + 3) / -10 = -6/-10 = 3/5

y - y1 = m(x - x1)
slope(m) = 3/5
(6,-3)..x1 = 6 and y1 = -3
now we sub
y - (-3) = 3/5(x - 6) =
y + 3 = 3/5(x - 6) <== one answer

y - y1 = m(x - x1)
slope(m) = 3/5
(-4,-9)....x1 = -4 and y1 = -9
now we sub
y - (-9) = 3/5(x - (-4) =
y + 9 = 3/5(x + 4) <== another answer

there are 2 answers....but the only one listed is answer D

5 0

3 years ago

Set up but do not solve for the appropriate particular solution yp for the differential equation y′′+4y=5xcos(2x) using the Meth

taurus [48]

Answer:

So, solution of the differential equation is

$y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

Step-by-step explanation:

We have the given differential equation: y′′+4y=5xcos(2x)

We use the Method of Undetermined Coefficients.

We first solve the homogeneous differential equation y′′+4y=0.

$y''+4y=0\\\\r^2+4=0\\\\r=\pm2i\\\\$

It is a homogeneous solution:

$y_h(t)=c_1e^{-2i t}+c_2e^{2i t}$

Now, we finding a particular solution.

$y_p(t)=A5x\cos 2x\\\\y'_p(t)=A5\cos 2x-A10x\sin 2x\\\\y''_p(t)=-A20\sin 2x-A20x\cos 2x\\\\\\\implies y''+4y=5x\cos 2x\\\\-A20\sin 2x-A20x\cos 2x+4\cdot A5x\cos 2x=5x\cos 2x\\\\-A20\sin 2x=5x\cos 2x\\\\A=-\frac{x}{4} \cot 2x\\$

we get

$y_p(t)=A5\cos 2x\\\\y_p(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x\\\\\\y(t)=y_p(t)+y_h(t)\\\\y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

So, solution of the differential equation is

$y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

7 0

3 years ago

Rewrite the function by completing the square.<br> f(x) = x2 – 10x + 44<br> +<br> f(x) = (x+

iVinArrow [24]

Answer:

$f(x)=(x-5)^{2}+19$

Step-by-step explanation:

we have

$f(x)=x^{2}-10x+44$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-44=x^{2}-10x$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$f(x)-44+25=x^{2}-10x+25$

$f(x)-19=x^{2}-10x+25$

Rewrite as perfect squares

$f(x)-19=(x-5)^{2}$

$f(x)=(x-5)^{2}+19$

8 0

4 years ago

Find the distance between (2a+2, 2b) and (2b+2, 2a), given that a>b.

Elina [12.6K]

Answer:

Distance = $2\sqrt{2}a-2\sqrt{2}b$

Step-by-step explanation:

We will use distance formula shown below to solve this:

Distance Formula: $\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Where

x_1 = 2a + 2

y_1 = 2b

x_2 = 2b+2

y_2 = 2a

Substituting, we solve for the expression for distance:

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\D=\sqrt{(2a-2b)^2+((2b+2)-(2a+2))^2}\\D=\sqrt{(2a-2b)^2+(2b+2-2a-2)^2}\\D=\sqrt{(2a-2b)^2+(2b-2a)^2}\\D=\sqrt{4a^2 -8ab+4b^2+4b^2-8ab+4a^2}\\D=\sqrt{8a^2-16ab+8b^2}\\D=\sqrt{(2\sqrt{2}a-2\sqrt{2}b)^2}\\D=2\sqrt{2}a-2\sqrt{2}b$

This is the expression in terms of a, and b, given a > b

7 0

3 years ago

Follow the rule to find the next three numbers in the pattern describe the pattern using the terms even and odd 1,6,11

____ [38]

Answer:

I need more explanation to be able to answer this question.

Step-by-step explanation:

1,6,11,15,18,20,21

5 0

3 years ago