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2 years ago

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For every O ion, two Na ions are needed to balance charges. Which ratio represents the relationship between Na and O? 1 Na:1 O 1

Na:2 O 2 Na:1 O 2 Na:2 O

2 answers:

quester [9]2 years ago

6 0

For every O ion, two Na ions are needed to balance charges. Which ratio represents the relationship between Na and O?

2 Na:1 O

lutik1710 [3]2 years ago

6 0

Answer:

Ratio represents the relationship between Na and O is 2:1.

Explanation:

Given that for every oxygen ion two sodium ions are needed to balance charge.

1 oxygen ion requires 2 sodium atoms

$O^{2-}+2Na^+\rightarrow Na_2O$

The ratio of oxygen ion to sodium ions is: $\frac{1}{2}$

So, on reversing the ratio we will get the ratio of sodium ions to oxygen ions:

$\frac{Na^+}{O^{2-}}=\frac{2}{1}$

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nordsb [41]

Answer: 0.077 M

Explanation:

Expression for rate law for first order kinetics is given by:

$k=\frac{2.303}{t}\log\frac{a}{a-x}$

where,

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t = time taken for decay process = 10 minutes

a = initial amount of the reactant= 0.859 M

a - x = amount left after decay process =?

Putting values in above equation, we get:

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An object is 70 um long and 47.66um wide. how long and wide is the object in km?

Ganezh [65]

Answer:

length = 7*10^(-8)km

width = 4.666*10^(-8) km

Explanation:

We know that:

1 μm = 1*10^(-6) m

and

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or

1m = 1*10^(-3) km

if we replace the meter in the first equation, we get:

1 μm = 1*10^(-6)*1*10^(-3) km

1 μm = 1*10^(-6 - 3)km

1 μm = 1*10^(-9)km

Now with this relationship we can transform our measures:

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L = 70*1*10^(-9)km = 7*10^(-8)km

And for width, we have 47.66um, this is 46.66 times 1*10^(-9)km, or:

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2 years ago

Find the range of a projectile launched at an angle of 30° with an initial velocity of 20m/s.

Tems11 [23]

Answer:

<em>The range is 35.35 m</em>

Explanation:

<u>Projectile Motion</u>

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Being vo the initial speed of the object, θ the initial launch angle, and $g=9.8m/s^2$ the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:

$\displaystyle d={\frac {v_o^{2}\sin(2\theta )}{g}}$

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2 years ago

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Answer:

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Explanation:

Given that,

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3 years ago