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andreyandreev [35.5K]
3 years ago
8

Can you help with this please

Physics
2 answers:
Vlad1618 [11]3 years ago
8 0
1 every light in your household is parallel this is useful bc as one goes out not all do as they would in a series circuit 2 plastic and glass they are common bc it does not let electricity travel from one place to another outside of it
Anton [14]3 years ago
7 0
I haven’t learned this yet sorry
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Pleaseeee help got this homework tomorrow ; if an object vibrates five times every second it has a frequency of ...?
AysviL [449]
Here's a tip: The unit of frequency ... Hertz or Hz ... means "per second". "Five times PER SECOND" is a frequency of 5 Hz.
8 0
3 years ago
Which of the following best describes the difference between type a and type b
Harrizon [31]
Is there supposed to be a picture? Next time try putting a picture
3 0
3 years ago
The density of aluminum is 2.70 g/ml. A piece of aluminum foil has a mass of 44 g. What is the volume of this piece of aluminum
anyanavicka [17]

Answer:

C) 16.3 ml

Explanation:

Density is equal to the ratio between the mass of an object and its volume:

d=\frac{m}{V}

where

m is the mass

V is the volume

In our problem, we know:

- density of aluminium: d=2.70 g/mL

- mass of the aluminium foil: m=44 g

So we can re-arrange the equation above and use these data to find the volume of the piece of aluminium foil:

V=\frac{m}{d}=\frac{44 g}{2.70 g/mL}=16.3 mL

7 0
3 years ago
Ultrasound with a frequency of 4.257 MHz can be used to produce images of the human body. If the speed of sound in the body is t
shutvik [7]

Answer:

2.49 * 10^(-4) m

Explanation:

Parameters given:

Frequency, f = 4.257 MHz = 4.257 * 10^6 Hz

Speed of sound in the body, v = 1.06 km/ = 1060 m/s

The speed of a wave is given as the product of its wavelength and frequency:

v = λf

Where λ = wavelength

This implies that:

λ = v/f

λ = (1060) / (4.257 * 10^6)

λ = 2.49 * 10^(-4) m

The wavelength of the sound in the body is 2.49 * 10^(-4) m.

4 0
2 years ago
The magnetic field at the center of a 1.50-cm-diameter loop is 2.70 mT . Part A. What is the current in the loop?
elixir [45]

Explanation:

It is given that,

Diameter of the circular loop, d = 1.5 cm

Radius of the circular loop, r = 0.0075 m

Magnetic field, B=2.7\ mT=2.7\times 10^{-3}\ T

(A) We need to find the current in the loop. The magnetic field in a circular loop is given by :

B=\dfrac{\mu_o I}{2r}

I=\dfrac{2Br}{\mu_o}

I=\dfrac{2\times 2.7\times 10^{-3}\times 0.0075}{4\pi \times 10^{-7}}

I = 32.22 A

(b) The magnetic field on a current carrying wire is given by :

B=\dfrac{\mu_o I}{2\pi r}

r=\dfrac{\mu_o I}{2\pi B}

r=\dfrac{4\pi \times 10^{-7}\times 32.22}{2\pi \times 2.7\times 10^{-3}}

r = 0.00238 m

r=2.38\times 10^{-3}\ m

Hence, this is the required solution.

8 0
3 years ago
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