Answer:
The metabolic power for starting flight=134.8W/kg
Explanation:
We are given that
Mass of starling, m=89 g=89/1000=0.089 kg
1 kg=1000 g
Power, P=12 W
Speed, v=11 m/s
We have to find the metabolic power for starting flight.
We know that
Metabolic power for starting flight=
Using the formula
Metabolic power for starting flight=
Metabolic power for starting flight=134.8W/kg
Hence, the metabolic power for starting flight=134.8W/kg
Answer:
Island arc
Explanation:
When two oceanic plates share a convergent type of plate boundary, the denser oceanic plate will subduct below the less dense oceanic plate. This will result in the formation of the subduction zone, where the rocks are being pulled down to the mantle. This subduction zone is typically marked by the presence of a narrow depression commonly known as an oceanic trench, that lies just above the zone.
The rocks of the subducting plate undergo partial melting and mix up with the magma that rises upwards towards the surface due to the force exerted by the convection currents. This later gives rise to the formation of volcanoes or a chain of volcanoes which are commonly known as an island arc.
Answer:
37.34372 kg
Explanation:
m = Mass
= Change in temperature
1 denotes water
2 denotes copper
c = Heat capacity
Heat is given by

In this case the heat transfer will be equal

Mass of copper block is 37.34372 kg
Answer:
1) Mass that needs to be converted at 100% efficiency is 0.3504 kg
2) Mass that needs to be converted at 30% efficiency is 1.168 kg
Explanation:
By the principle of mass energy equivalence we have

where,
'E' is the energy produced
'm' is the mass consumed
'c' is the velocity of light in free space
Now the energy produced by the reactor in 1 year equals

Thus the mass that is covertred at 100% efficiency is

Part 2)
At 30% efficiency the mass converted equals

C standards are based on observable, reproducible natural phenomena.