1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SVEN [57.7K]
2 years ago
13

if the magnitudes of the forces vary with time as F1=Ct and F = 2Ct, where C equals to 7.5 N/s and t is time, find the time t0 a

t which the tension in the string equals to 27.0N
Physics
1 answer:
Degger [83]2 years ago
4 0

Answer:

The tension in the string is equal to Ct

And the time t0 when the rension in the string is 27N is 3.6s.

Explanation:

An approach to solving this problem jnvolves looking at the whole system as one body by drawing an imaginary box around both bodies and taking summation of the forces. This gives F2 - F1 = Ct. This is only possible assuming the string is massless and does not stretch, that way transmitting the force applied across it undiminished.

So T = Ct

When T = 27N then t = T/C = 27/7.5 = 3.6s

You might be interested in
A bug splats against the windshield of a car traveling at high speeds down a backcountry road. Which statement correctly compare
zvonat [6]

Answer:

C. The bug's change in momentum is equal to the car's change in momentum.

Explanation:

As we know by Newton's 2nd law

F = \frac{\Delta P}{\Delta t}

here we have also know that when car hits the bug then force applied by wind shield on the bug is same as the force applied by the bug on the car's wind shield as per Newton's III law

F_{12} = F_{21}

so we know that

\frac{\Delta P_{12}}{\Delta t} = \frac{\Delta P_{21}}{\Delta t}

so we have

\Delta P_{12} = \Delta P_{21}

so correct answer will be

C. The bug's change in momentum is equal to the car's change in momentum.

6 0
3 years ago
Using energy considerations, calculate the average force (in N) a 62.0 kg sprinter exerts backward on the track to accelerate fr
slava [35]

Answer:

69.68 N

Explanation:

Work done is equal to change in kinetic energy

W = ΔK = Kf - Ki = \frac{1}{2} mv^{2} _{f}  - \frac{1}{2} mv^{2} _{i}

W = F_{total} .d

where m = mass of the sprinter

vf = final velocity

vi = initial velocity

W  = workdone

kf = final kinetic energy

ki = initial kinetic energy

d = distance traveled

Ftotal = total force

vf = 8m/s

vi= 2m/s

d = 25m

m = 60kg

inserting parameters to get:

W = ΔK = Kf - Ki = \frac{1}{2} mv^{2} _{f}  - \frac{1}{2} mv^{2} _{i}

F_{total} .d =\frac{1}{2} mv^{2} _{f}  - \frac{1}{2} mv^{2} _{i}

F_{total} = \frac{\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}}{d}

F_{total=} \frac{\frac{1}{2} X 62 X6^{2} -\frac{1}{2} X 62 X2^{2} }{25}

= 39.7

we know that the force the sprinter exerted F sprinter, the force of the headwind Fwind = 30N

F_{sprinter} = F_{total} + F_{wind}  = 39.7 + 30 = 69.68 N

7 0
3 years ago
Read 2 more answers
What is the average acceleration of a car that goes from rest to 60 km/h in 8 seconds?  Be sure to show all work to support your
wel
The average acceleration can be found by dividing the final speed by the time taken to reach said point so in this case you divide 60 by 8 resulting in 7.5 which will be your answer
5 0
2 years ago
Read 2 more answers
How much time will it take a car travelling at 88 km/hr (55 mi/hr) to travel 500km
Elis [28]
<span>500 km x (1 hr/88 km) = 5.68 hrs</span>
4 0
3 years ago
a college student rests a backpack upon his shoulder. the pack is suspended motionless by one strap from one shoulder.
Minchanka [31]

The student's shoulder supports the weight of the bag.

<h3>What is the free body diagram?</h3>

Free-body diagrams are utilized to display the relative direction and strength of all forces that are being applied to an item in a certain scenario. A unique illustration of the geometric diagrams that were covered in a previous lesson is the free-body diagram. We will make use of these graphics throughout the entire study of physics.

A university student is carrying a backpack. One strap is hanging the rucksack immobile from one shoulder.

The weight of the backpack is balanced by the shoulder of the student.

The free-body diagram is attached below.

More about the free body diagram link is given below.

brainly.com/question/24087893

#SPJ4

4 0
1 year ago
Other questions:
  • How can a heavy moving van have the same momentum as a small motorcycle?
    8·1 answer
  • Wave A has a wavelength of 2 meters and a frequency of 1.5 Hz . calculate the wave's speed
    9·1 answer
  • A small satellite being designed requires a nitrogen storage tank to store propellant for the cold gas thruster used to maintain
    14·1 answer
  • A loop of area 0.0633 m^2 is oriented perpendicular (0 deg) to a magnetic field. The magnetic field changes in strength from 0.8
    11·1 answer
  • Describe and explain the motion of a small ball floating on a pond when waves travel across the pond
    8·1 answer
  • Chord progressions that move to resting points that release tension are called
    13·1 answer
  • The “turning effect of a force” (T = F * r) is:
    7·1 answer
  • How do i convert 0.25hr into minutes
    5·1 answer
  • List examples of how the Bill of Rights protects you:<br> .<br> .<br> .<br> .<br> .
    9·1 answer
  • A cat jumps from 2.5-meter-tall bookshelf to a 1.3-meter-tall countertop. If the cat
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!