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SVEN [57.7K]
2 years ago
13

if the magnitudes of the forces vary with time as F1=Ct and F = 2Ct, where C equals to 7.5 N/s and t is time, find the time t0 a

t which the tension in the string equals to 27.0N
Physics
1 answer:
Degger [83]2 years ago
4 0

Answer:

The tension in the string is equal to Ct

And the time t0 when the rension in the string is 27N is 3.6s.

Explanation:

An approach to solving this problem jnvolves looking at the whole system as one body by drawing an imaginary box around both bodies and taking summation of the forces. This gives F2 - F1 = Ct. This is only possible assuming the string is massless and does not stretch, that way transmitting the force applied across it undiminished.

So T = Ct

When T = 27N then t = T/C = 27/7.5 = 3.6s

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Who has the most power? athlete A (bench presses 100 kg over 0.6 m in 0.5 s) athlete B (bench presses 150 kg over 0.6 m in 1.0 s
MrRissso [65]

Answer:

Athlete A

Explanation:

Power is the rate of doing work and it is calculated as follows:

Power = work done/time taken = mgh/t

(for work being done against gravity)

So for athlete A

P = (100 kg * 9.8 N/kg* 0.6m)/0.5 s = 1176 W

For athlete B

P = (150 kg * 9.8 N/kg* 0.6m)/1 s = 882 W

For athlete C

P = (200 kg * 9.8 N/kg* 0.6m)/2 s = 588 W

For athlete D

P = (250 kg * 9.8 N/kg* 0.6m)/2.5 s = 588

4 0
2 years ago
A 5.6 cm diameter parallel-plate capacitor has a 0.58 mm gap. What is the displacement current in the capacitor if the potential
BARSIC [14]

Answer:

1.88\cdot 10^{-5} A

Explanation:

The capacitance of a parallel plate capacitor is given by:

C=\frac{\epsilon_0 A}{d} (1)

where

\epsilon_0 is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

The charge stored on the capacitor is given by

Q=CV (2)

where C is the capacitance and V is the voltage across the capacitor.

The displacement current in the capacitor is given by

J=\frac{Q}{t} (3)

where t is the time elapsed

Substituting (1) and (2) into (3), we find an expression for the displacement current:

J=\frac{CV}{t}=\frac{\epsilon_0 A}{d} \frac{V}{t}

where we have

A=\pi (\frac{d}{2})^2=\pi (\frac{0.056 m}{2})^2=2.46\cdot 10^{-3} m^2

d = 0.58 mm = 5.8\cdot 10^{-4} m

\frac{V}{t}=500,000 V/s

Substituting into the equation, we find

J=\frac{(8.85\cdot 10^{-12} F/m)(2.46\cdot 10^{-3} m^2)}{5.8\cdot 10^{-4}m}(500,000 V/s)=1.88\cdot 10^{-5} A

6 0
3 years ago
If manuel weighs 375 n and is holding the box. how much force is the floor exerting on him? (include direction)
denis23 [38]
<span> The box is exerting a force of its weight. So we'll use W=mg (Note: you can use the notation F=ma, doesn't matter since weight IS a force.) We can call g negative since it's directed down towards the earth. 
</span>
<span>W = 5kg(-9.8 m/(s^2)) = -49 N 
</span>
<span>Thus, the box exerts a force of 49N downwards. </span>
4 0
3 years ago
A householder has a 10.8 kW electric shower installed in the bathroom. Calculate the current drawn from the mains electricity su
emmasim [6.3K]

Answer:

90 A

Explanation:

Applying,

P = VI.............. Equation 1

Where P = Power, V = Supply voltage, I = current.

Make I the subject of the equation

I = P/V.............. Equation 2

From the question,

Assuming the Voltage of the main electric supply is 120 V

Given: P = 10.8 kW = 10800 W, V = 120 V (household voltage)

Substitute these values into equation 2

I = 10800/120

I = 90 A

5 0
3 years ago
During the _____ collision, the vehfirst second third fourthicle comes to an abrupt stop.
Vladimir79 [104]
During the first collision, the vehicle comes to an abrupt stop. 
6 0
3 years ago
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