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2 years ago

What is E equal to in relativity?

Physics

2 answers:

vladimir1956 [14]2 years ago

7 0

$\huge \underline \mathtt \colorbox{cyan}{E=mc squared}$

(E=mc^2)

<h3>Where:</h3>

m is mass

And c is a constant for speed of light

spayn [35]2 years ago

5 0

Answer:

One of the most famous and well-known equations in all of human history, E = mc^2, translates to "energy is equal to mass times the speed of light squared." In other words, wrote PBS Nova, energy (E) and mass (m) are interchangeable. They are, in fact, just different forms of the same thing.

Explanation:

this is right answer

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A ray is incident on a film of thickness t and the index of refraction n=1.6 at an angle θ = 35 degrees. Find the angle of refra

lidiya [134]

Answer

Given,

refractive index of film, n = 1.6

refractive index of air, n' = 1

angle of incidence, i = 35°

angle of refraction, r = ?

Using Snell's law

n' sin i = n sin r

1 x sin 35° = 1.6 x sin r

r = 21°

Angle of refraction is equal to 21°.

Now,

distance at which refractive angle comes out

d = 2.5 mm

α be the angle with horizontal surface and incident ray.

α = 90°-21° = 69°

t be the thickness of the film.

So,

$tan \alpha = \dfrac{t}{d/2}$

$tan 61^0 = \dfrac{t}{2.5/2}$

t = 2.26 mm

Hence, the thickness of the film is equal to 2.26 mm.

4 0

3 years ago

Choose the situation below in which the force applied is the greatest.

Gnesinka [82]

Answer:

Explanation:

We know the formula for Work to be:

W = f * d

Where W is work done

f is force

d is the distance

Work = 50

Distance = 50

So, Force is:

Force = 50/50 = 1

Work = 400

Distance = 80

Force = 400/80 = 5

Work = 365

Distance = 73

Force = 365/73 = 5

Work = 144

Distance = 16

Force = 144/16 = 9

Hence, D is the situation in which the force applied is the greatest.

6 0

3 years ago

Calculate the work done by a 50.0 N force on an object as it moves 9.00 m, if the force is oriented at an angle of 135° from the

aivan3 [116]

Answer:

Work done, W = -318.19 Joules

Explanation:

It is given that,

Force acting on the object, F = 50 N

Distance covered by the force, d = 9 m

Angle between the force and the distance traveled, $\theta=135^{\circ}$

The work done by an object is equal to the product of force and distance traveled. It is equal to the dot product of force and the distance. Mathematically, it is given by :

$W=Fd\ cos\theta$