You don't even have to look up the definition of 'standard deviation'. You only
have to remember that 'smaller standard deviation' means 'less spread-out'.
First, let's find the mean (average). It's not supposed to change:
1/7th of (65 + 71 + 77 + 80 + 82 + 90 + 96) = 561/7 = <u>80 and 1/7</u> .
Now, just pick 7 scores that total 561 and are all bunched up.
The easiest way would be 80, 80, 80, 80, 80, 80, 81 .
But that's so easy that it feels like cheating.
Let's say <u>77, 78, 79, 80, 81, 82, and 84</u> .
If 28 tiles is placed in 7 rows then each row has 4 tiles.
<u>Step-by-step explanation:</u>
The total number of tiles given =28.
The number of rows = 7.
The number of tiles in each row is given by diving the total number of tiles given by the number of rows.
No of tiles in each row=
.
No of tiles in each row =
.
No of tiles in each row = 4.
Note: You can replace the values according to the given values.
Answer:
(x, y) = (18, 5)
Step-by-step explanation:
Assuming the three lines meet at a single point at lower left (the figure is sloppily drawn), the angle (3x)°+49° is a corresponding angle to (7x-23)°. That means they have the same measure:
3x +49 = 7x -23
72 = 4x . . . . . . . . . add 23-3x
18 = x . . . . . . . . . . . divide by 4
__
Angles (3x)° and (11y-1)° are "corresponding" angles, so are congruent.
3x = 11y -1
3(18) +1 = 11y . . . . add 1, fill in the value of x
55/11 = y = 5 . . . . divide by 11
The values of x and y are 18 and 5, respectively.
The answer for the question is
Answer: Most likely, the value of w is 5 units.
Step-by-step explanation: P = 2L + 2w
If the perimeter is 28, the side lengths must be less than 14, otherwise there is no width, just two lines on top of one another.
If the width is 7, then all four sides would be 7 units, and <u>that would create a square</u>-- which is a type of rectangle-- but probably not what this question is about.
A width of 5 units makes sense, 2w would be 10, leaving 28-10 = 18 to be divided by 2 for lengths of 9
The rectangle would have a width of 5 units and a length of 9 units.