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MAXImum [283]
3 years ago
11

A ball is rolled uphill a distance of 5 meters before it slows, stops, and begins to roll back. The ball rolls downhill 9 meters

before coming to rest against a tree. What is the amount of displacement of the ball?
Physics
1 answer:
Zepler [3.9K]3 years ago
6 0
The magnitude of the ball's displacement when the ball is rolled uphill with a 5 meters before it slows, stops and begins to roll back and the ball rolls downhill 9 meters before coming to rest is 4 meter. Just subtract 9 meters with 5 meters. Therefore the answer is 4 meters. 
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Cars cross a certain point on the highway in accordance with a Poisson process with rate = 3 per minute. If Al runs across the h
Svetradugi [14.3K]

Answer:

The probability is 0.2212

Solution:

As per the question:

Poisson rate, \lambda = 3/min = \frac{3}{60}\ s = 0.05\ s

Now,

Let

X: time of waiting for the next vehicle on the highway

Now,

To find the probability of the next vehicle to arrive after 10 s

The probability distribution function is given by:

f(x) = \lambda e^{- \lambda x}

Now,

P(X < x) = 1 - e^{- \lambda x}

P(X \leq x) = 1 - e^{- 0.05 x}

For X> 0,

P(X > x) = e^{- \lambda x}

P(X < 5) = 1 - e^{- 5\lambda} = 1 - e^{- 0.25} = 1 - 0.7788 = 0.2212

4 0
3 years ago
Venus has an average distance to the sun of 0.723 AU. In two or more complete sentences, explain how to calculate the orbital pe
Mice21 [21]

As per the question the distance of venus from sun is given as 0.723 AU

We have been asked to calculate the time period of the planet venus.

As per kepler's laws of planetary motion the square of time period of planet is directly proportional to the cube of semi major axis. mathematically

                                        T^{2} \alpha R^{3}

                                         ⇒ T^{2} = KR^{3} where is k is the proportionality  constant

We may solve this problem by comparing with the time period of the earth . We know that time period of earth is 365.5 days

Hence T_{1} =365.5 days

The distance of sun from earth is taken as 1 AU i.e the mean distance of earth from sun

Hence R_{1} =1 AU

The distance of venus from sun is 0.723 AU i.eR_{2} =0.723

From keplers law we know that-\frac{T_{1} ^{2} }{T_{2} ^{2} } =\frac{R_{1} ^{3} }{R_{2} ^{3} }

                            ⇒T_{2} ^{2} =T_{1} ^{2} *\frac{R_{2} ^{3} }{R_{1} ^{3} }

Putting the values mentioned above we get-

                                      T_{2} ^{2} =50,350.132851075

                                         ⇒ T_{2} =\sqrt{50,350.132851075}

                                        ⇒T_{2} = 224.388352752710 days.

Hence the time period of venus is 224.388352752710 days

                                         

                     






                           

7 0
4 years ago
Read 2 more answers
If a rocket was shot into outer space and never collided with any planets or asteroids, what would happen to the rocket once it
lord [1]

Answer:

Then the rocket will slow down until the end of gas and when all the gases are ended, then it stops at the highest point of space and falls back to earth.

<h2><em><u>NOT</u></em><em><u> </u></em><em><u>COPIED</u></em><em><u> </u></em><em><u>ANSWER</u></em></h2>
4 0
3 years ago
What is the frequency of UV light that has an energy of 2.39 × 10 -18 J?
Setler [38]

Answer:

3.60 × 10^{15} Hz

Explanation:

\frac{2.39 * 10^{-18} J}{6.63 * 10^{-34} J.s}

4 0
3 years ago
You are working as a summer intern for the Illinois Department of Natural Resources (DNR) and are assigned to some initial work
hammer [34]

Answer:

1)   F = 71.6 N , 2)    F = 120.2 N , 3)  P_m=  68.600 Pa, 4)  V = 2.4210-5 m³

Explanation:

This is a problem of fluid mechanics, to find the force we must use its definition

         P = F / A

         F = P A

The area of ​​the circular pipe is

         A = π r² = π d²/4

The pressure is given by the expression

         P = P_atm + ρ g h

1) the force on the outer side is

       P = P_atm

we substitute in the expression of force

         F = P_atm π d² / 4

         

let's calculate

         F = 1,013 10⁵ π 0.03²/4

         F = 7.16 10¹ N

         F = 71.6 N

2) the force on the inner side

  the pressure

       P = P_atm + ρ g h

       P = 1,015 10⁵ + 1,000 9.8 7

        P = 1,701 10⁵ Pa

        F = 1,701 10⁵ π 0.03² / 4

        F = 1,202 10²

        F = 120.2 N

3) manometric pressure

       Pm = ρ g h

       P m = 1000 9.8  7

       P_m=  68.600 Pa

4) In this part they ask for the volume that comes out in time t= 3 h

   to calculate this volume we can use the flow ratio

         Q = A v

          V t = A v

          V = A v / t

sent is the velocity of the water that comes out, to calculate it we use the Bernoulli equation

we will use index 1 for the lake surface and ionice 2 apa the position of the plug

           P₁ + ρ g v₁² + ρ g y₁ = P₂ + ρ g v₂² + ρ g y₂

As the lake has much more capacity than the pipeline, the velocity of the surface of the lake is peeling, in this case we approximate it steel

           (P₁-P₂) + ρ G (y₁ -y₂) = ρ g v₂²

           1000 9.8 v₂² = ρ g h + 1000 9.8 (7-0)

             9800 v₂² = 1000 9.8 7 + 68600

              v₂ = √ (137200)

               v₂ = 370.4 m / s

             t = 3 h (3600s / h) = 10800 s

     

we substitute in the volume equation

             V = π d²/4   370.4 / 10800

             V = 2.4210-5 m³

4 0
3 years ago
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