Answer:

Explanation:
Translation:
- <em>What volume will 12g of iron occupy?</em>
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<h2>Solution</h2>
<em />
<em>Iron</em> is a solid substance at room temperature. You can find the <em>volume</em> of solids (and of not solids) using the density.

You can obtaindthe density of most pure substances in the internet. The density of<em> iron</em> at room temperature is 7.874 g/cm³.
Thus, substituting in the formula, you get:

The answer is rounded to two significant figures because the input, 12g, has two significant figures.
<span>The lattice structure in a metal is weaker than the lattice structure of an ionic compound. This is because the metals have free electrons which can freely move around while ionic compounds are strongly bonded. Hope this answers the question.</span>
Answer:
39.2 g
Explanation:
- 2Ni₂O₃(s) ⟶ 4Ni(s) + 3O₂(g)
First we <u>convert 55.3 grams of Ni₂O₃ into moles of Ni₂O₃</u>, using its<em> molar mass</em>:
- 55.3 g ÷ 165.39 g/mol = 0.334 mol Ni₂O₃
Then we <u>convert 0.334 moles of Ni₂O₃ into moles of Ni</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:
- 0.334 mol Ni₂O₃ *
= 0.668 mol Ni
Finally we <u>calculate how much do 0.668 Ni moles weigh</u>, using the<em> molar mass of Ni </em>:
- 0.668 mol Ni * 58.69 g/mol = 39.2 g