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Oliga [24]
2 years ago
8

Given A=125.0=0.4 and 25.0=0.1 calculate A-B​

Physics
1 answer:
kicyunya [14]2 years ago
6 0

Answer: Find an answer to your question given A=125.0=0.4 and 25.0=0.1 calculate A-B​

Explanation:

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An object that is 3 times higher than another object of the same mass will
uranmaximum [27]

Answer: I feel that 3 is the answer

Explanation: Let there be 2 objects, A and B

A is at height of 5m whereas B is at height of 15m

so over here let the gravitational potential energy of A be x

and since B is 3 times higher than A B=3x

Since, earth is considered to be the point where gravitational potenial is 0

So hence forth and object 3 times up will have 3 times the gravitational potential energy of A

3 0
3 years ago
During a medieval siege of a castle, the attacking army uses a trebuchet to heavy stones at the castle the trebuchet launches th
vlada-n [284]

Answer:

Explanation:

The question relates to time of flight of a projectile .

Time of flight = 2 u sinθ / g

u is speed of projectile , θ is angle of projectile

= 2 x 48.5 sin42 / 9.8

= 6.6 seconds  .

Maximum height attained

= u² sin²θ / g

= 48.5² sin²42 / 9.8

= 107.47 m .

7 0
2 years ago
Suppose you throw a ball vertically upward with a speed of 49 m/s. Neglecting air friction, what would be the height of the ball
vlabodo [156]

Answer:

78.4 m

Explanation:

Using newton's equation of motion,

S = ut + 1/2gt²......................... Equation 1

Where S = Height, t = time, u = initial velocity, g = acceleration due to gravity.

Note: Taking upward to be negative, and down ward positive

Given: u = 49 m/s, t = 2.0 s, g = -9.8 m/s²

Substitute into equation 1

S = 49(2) - 1/2(9.8)(2)²

S = 98 - 19.6

S = 78.4 m

Hence the height of the ball two seconds later = 78.4 m

6 0
2 years ago
Allison wants to determine the density of a bouncing ball. which metric measurements must she use?
lubasha [3.4K]
Density depends on mass and volume so option D is correct answer. Hope this helps!
3 0
3 years ago
Master of physics needed
Delicious77 [7]
Hey JayDilla, I get 1/3.  Here's how:
Kinetic energy due to linear motion is:
E_{linear}= \frac{1}{2}mv^2
where
v=r \omega
giving
E_{linear}= \frac{1}{2}mr^2 \omega ^2

The rotational part requires the moment of inertia of a solid cylinder
I_{cyl} =  \frac{1}{2}mr^2
Then the rotational kinetic energy is
E_{rot}= \frac{1}{2}I \omega ^2= \frac{1}{4}mr^2 \omega ^2
Adding the two types of energy and factoring out common terms gives
\frac{1}{2}mr^2 \omega ^2(1+ \frac{1}{2})
Here the "1" in the parenthesis is due to linear motion and the "1/2" is due to the rotational part.  Since this gives a total of 3/2 altogether, and the rotational part is due to a third of this (1/2), I say it's 1/3.

8 0
3 years ago
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