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2 years ago

Given A=125.0=0.4 and 25.0=0.1 calculate A-B

Physics

1 answer:

kicyunya [14]2 years ago

6 0

Answer: Find an answer to your question given A=125.0=0.4 and 25.0=0.1 calculate A-B

Explanation:

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Aleksandr-060686 [28]

Answer:

A factor of 2*4 = 8

Explanation:

F_g = (G*m1*m2)/r^2

where m1 and m2 are the two masses, G is Newton's gravitational constant, and r is the distance between the center of mass of the two objects.

So, if you double m1 and quadruple m2:

m1' = 2*m1

m2' = 4*m2

Then F_g' = (G*m1'*m2')/r^2 = (G*2*m1*4*m2)/r^2 = 8*(G*m1*m2)/r^2 = 8*F_g

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2 years ago

1. An object has a mass of 10g and a volume of 50mL. What is the density?

Alona [7]

1. 0.2 g/mL

The relationship between mass, density and volume of an object is

$d=\frac{m}{V}$

where

d is the density

m is the mass

V is the volume

For the object in this problem, we have

m = 10 g

V = 50 mL

Substituting into the equation,

$d=\frac{10}{50}=0.2 g/mL$

2. 10 mL

In this exercise we know:

- The density of the object: d = 2 g/mL

- The mass of the object: m = 20 g

Therefore, we can re-arrange the previous equation to find the volume:

$V=\frac{m}{d}$

And substituting values into the equation, we find

$V=\frac{20}{2}=10 mL$

7 0

3 years ago

High priority should be given for the development and use oc hydroelectricity justify with reason

olga2289 [7]

Answer:

because hydroelectricity is generate from water and it is considered as a perpetual resources and produce the large capacity of electricity which helps in the indicator of development

5 0

2 years ago

One circuit contains only an ac generator and a resistor, and the rms current in this circuit is IR. Another circuit contains on

snow_tiger [21]

Answer:

1/3 times.

Explanation:

Let V₀ be the peak voltage .

IR ( rms ) = ( V₀ / √2 R )

R is value of resistance

IC = ( V₀ ωC / √2 )

( 1 / ωC is reactance of capacitance in ac circuit )

$\frac{I_R}{I_C} =\frac{\frac{V_0}{\sqrt{2}R } }{\frac{V_0\omega C}{\sqrt{2} } }$

= $\frac{I_R}{I_C} = \frac{1}{\omega C R}$

When frequency is tripled angular frequency will also be tripled

hence the ratio $\frac{I_R}{I_C}$ becomes 1/3 times.

7 0

3 years ago

At the presentation ceremony, a championship bowler is presented a 1.60-kg trophy which he holds at arm's length, a distance of

nikdorinn [45]

Answer:

a)10.28 Nm

b)9.93 Nm

Explanation:

Let g = 9.81m/s2. First we can calculate the weight of the trophy

W = mg = 1.6 * 9.81 = 15.696 N

(a) The torque is product of force and its moment arm

T = WL = 15.696 * 0.655 = 10.28 Nm

(b) Suppose his arm makes an angle of 15 degree with respect to the horizontal line. We can still calculate the arm length, or the horizontal distance from the trophy to the champion:

$L_2 = Lcos(15^0) = 0.655cos(15^0) = 0.655*0.966 = 0.633 m$

Again, torque is product of force and its moment arm

$T_2 = WL_2 = 15.696 * 0.633 = 9.93 Nm$

8 0

3 years ago

Given A=125.0=0.4 and 25.0=0.1 calculate A-B​

Given A=125.0=0.4 and 25.0=0.1 calculate A-B