Question

Balance copper (II) sulphate + sodium hydroxide-> copper (II) hydroxide + sodium sulphate​

Answer 1

Answer:

CuSO4 + 2NaOh -> CuOH2 + Na2SO4

Explanation:

The sulphate ion is basically an anion(negatively charged ion) with a charge of overall -2. The hydroxide ion is also an anion with a charge of overall -1. Copper ion is described as copper (II) meaning that it has a charge of +2. Sodium is an alkali metal meaning that it has a charge of +1.

Now we know that the end results are copper hydroxide and sodium sulphate. Since the copper ion has a charge of +2, two hydroxide ions should bond with copper. The sulphate ion has a charge of -2, meaning that two sodium ions should bond with sulphate. There should be two sodium ions to bond with one sulphate ion and two hydroxide ions to bond with one copper ion. Therefore, the coeffiecient for sodium hydroxide should be two.