What is the primary difference between a molecule and a compound?

Chemistry

2 answers:

Korvikt [17]3 years ago

5 0

The Answer is A

Hope this helped ;)

Harlamova29_29 [7]3 years ago

4 0

Answer:

A. "All molecules are compounds, but not all compounds are molecules"

Explanation:

An example of a compound-molecule is oxygen. The elemenal is O, because the periodic table isn't describing molecules, it's describing atoms. The molecule is O2 because it takes 2 O atoms to make a molecule of oxygen.

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One gram of Sn was electroplated from a SnCl, solution in 30 minutes. What was the current used?

Andrews [41]

Answer:

0.903 A

Explanation:

We have given mass of Sn = 1 gram

Time t=30 minutes=30×60=1800 sec

According to Faraday law m=zit

Where z is electron chemical equivalent

z is calculated by $z=\frac{atomic\ mass}{nF}$ where n is number of element and F is Faraday constant

So $z=\frac{atomic\ mass}{nF}=\frac{118.71}{2\times 96500}=0.000615$

So $1=0.000615\times i\times 1800$

i =0.903 A

4 0

4 years ago

a water sample is found to have a cl- content of 100ppm as nacl what is the concentration of chloride in moles per liter

ladessa [460]

Answer:

The concentration of chloride ion is $2.82\times10^{-3}\;mol/L$

Explanation:

We know that 1 ppm is equal to 1 mg/L.

So, the $Cl^-$ content 100 ppm suggests the presence of 100 mg of $Cl^-$ in 1 L of solution.

The molar mass of $Cl^-$ is equal to the molar mass of Cl atom as the mass of the excess electron in $Cl^-$ is negligible as compared to the mass of Cl atom.

So, the molar mass of $Cl^-$ is 35.453 g/mol.

Number of moles = (Mass)/(Molar mass)

Hence, the number of moles (N) of $Cl^-$ present in 100 mg (0.100 g) of $Cl^-$ is calculated as shown below:

$N=\frac{0.100\;g}{35.453\;g/mol}=2.82\times 10^{-3}\;mol$