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Alex17521 [72]
3 years ago
7

What volume of 2M hydrochloric acid will neutralise 25 cm3 sodium carbonate?

Chemistry
1 answer:
AysviL [449]3 years ago
8 0
In sodium carbonate I believe the carbonate is considered the base and that the HCl will react with the carbonate to produce bicarbonate (HCO₃). Due to that, I think the chemical equation should be HCl+NaCO₃→HCO₃+NaCl.

To neutralize the solution, you need to have equal amounts H⁺ and CO₃⁻ which means that you need to have equal amounts HCl and NaCO₃.  To find this you need to know how many moles of NaCO₃ there are in the 25mL solution since that is the number of moles of HCl you need.  You would then divide the number of moles of HCl needed by 2M to find the volume of HCl needed.  

With the information given I don't think you can answer this.  You need to know what the concentration of the sodium carbonate is and with out that value you can't determine how many moles of sodium carbonate there are.  You need to know how many moles of sodium carbonate you have in order to know how much 2M hydrochloric acid is needed to neutralize it.

The process you would usually use is:
(0.025L NaCO₃)×(molarity of NaCO₃)=moles NaCO₃
moles NaCO₃=moles HCl needed to neutralize
(moles HCl needed to neutralize)/2M=Liters of HCl needed to neutralize

Let me know if the question came with any more information but right now I don't think it can be solved.

I hope this helps.  Let me know if anything is unclear.

Also, since this reaction is between a strong acid and weak base, when you neutralize it with the strong acid the pH of the solution will not be 7.  It will most likely be under seven since HCO₃ is being produced which is the conjugate acid of CO₃ and therefore create a slightly acidic solution at the equivalence point (the equivalence point is another way of saying the solution was neutralized).  You probably don't need to know this for the scope of your class but I thought it was worth mentioning since later on you will have to deal with this fact.
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How much energy is required to heat 36.0 g H2O from a liquid at 65°C to a gas at 115°C? The following physical data may be usefu
In-s [12.5K]

Answer:

energy required=qnet=87.75kJ

Explanation:

we will do it in three seperate step and then add up those value.

first step is to heat the sample of water upto 100C i.e upto boiling pont. because just after this sample of water started vaporization.

q 1= m c (T2-T1)

q1 = 36.0 g (4.18 J/gC) (100 - 65 C)

q1 = 5267 J =5.267kJ

next is to vaporize the sample at 100C

q2 = 36.0 g / 18.0 g/mol X 40.7 kJ/mol

q2= 81.4 kJ

Finally, heat the steam upto 115C

q3 = m c (T2-T1)

q 3= 36.0 g (2.01 J/gC)(115-100C)

q3 = 1085 J =1.085kJ

qnet=q1 +q2 +q3

energy required=qnet=87.75kJ

8 0
3 years ago
The thallium (present as Tl2SO4) in a 9.486-g pesticide sample was precipitated as thallium(I) iodide. Calculate the mass percen
tino4ka555 [31]

Answer: The mass percentage of Tl_2SO_4 is 5.86%

Explanation:

To calculate the mass percentage of Tl_2SO_4 in the sample it is necessary to know the mass of the solute (Tl_2SO_4 in this case), and the mass of the solution (pesticide sample, whose mass is explicit in the letter of the problem).

To calculate the mass of the solute, we must take the mass of the TlI precipitate.  We can establish a relation between the mass of TlI and Tl_2SO_4 using the stoichiometry of the compounds:

moles\ of\ TlI = \frac{0.1824 g}{331.27\frac{g}{mol} } = 5.51*10^{-4}\ mol.

Since for every mole of Tl in TlI there are two moles of Tl in Tl_2SO_4, we have:

moles\ of\ Tl_2SO_4 = 2 * moles\ of\ TlI = 1,102*10^{-3}\ mol

Using the molar mass of Tl_2SO_4 we have:

mass\ of\ Tl_2SO_4 = 1,102*10^{-3}\ mol * 504.83\ \frac{g}{mol}= 0.56\ g

Finally, we can use the mass percentage formula:

mass\ percentage = (\frac{solute\ mass}{solution\ mass} )*100 = (\frac{mass\ of\ Tl_2SO_4}{pesticide\ sample\ mass})*100 = (\frac{0.56g}{9.486g})*100 = 5.86\%

6 0
2 years ago
What is the mass number of an ion with 107 electrons, 158 neutrons, and a 1 charge?
vredina [299]
No of protons=107+1=108
No. Of neutrons=158
Mass no. =166
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3 years ago
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Explanation:

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3 years ago
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AURORKA [14]

Answer:

hi

Explanation:

1 east

2 the flower bud for cotton and for jute the leaves

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