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3 years ago

A particle that has the electron configuration 1s²2s²2p³ would:

Chemistry

1 answer:

notka56 [123]3 years ago

5 0

Answer:

Have 2 filled orbitals and 3 partially filled orbitals.

Explanation:

Hello there!

In this case, according to the given information of the electron configuration for that particle; it is possible for us to infer it has 5 valence electrons, as the electrons on its outermost shell (2). Moreover, we undertand this particle needs three bonds, does not have neither the electron configuration of a noble gas which ends by p⁶ nor that of an alkali earth metal as it ends by s².

Therefore, we infer the correct answer is Have 2 filled orbitals and 3 partially filled orbitals because according to the Hund's rule, the s orbital is fulfilled and the p orbital has 1 electron orbital fulfilled and two partially filled orbitals.

Regards!

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4 years ago

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2 years ago

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There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In

tatyana61 [14]

Answer:

-470.4 kJ/mol

Explanation:

Balanced reactions equations are as follows.

CaC2 (s) + 2H2O (l) â C2H2 (g) + CaOH2 (s) ÎH=â414.kJ

6C2H2 (g) + 3CO2 (g) + 4H2O (g) â 5CH2CHCO2H (g) ÎH=132.kJ

To get the 6 C2H2 we need to multiply first equation by 6

Then we get

6CaC2 (s) + 12H2O (l) â 6C2H2 (g) + 6CaOH2 (s) ÎH=â414.kJ * 6 = -2484 kJ

6C2H2 (g) + 3CO2 (g) + 4H2O (g) â 5CH2CHCO2H (g) ÎH=132.kJ

So the total energy produced = -2484 kJ + 132.0 kJ = -2352 kJ

This amount of energy is given out for the 5 moles of acid

So lets convert it for 1 mol

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3 years ago

The boiling point of ethanol (C₂H₅OH) is 78.5°C. What is the boiling point of a solution of 6.4 g of vanillin M = 152.14 g/mol)

Gwar [14]

The boiling point of a solution of 6.4 g of vanillin in 50.0g of ethanol is 77.47 degree C.

Change in boiling point of solution

ΔTb = (Kb)(m), where

ΔTb = change in temperature

Kb = elevation constant = 1.22 °C./m

m = molality of the solution

Following the calculation of the moles of vanillin, the molality of vanillin in ethanol will be determined..

Moles of vanillin = 6.4g / 152.12g/mol = 0.042 mol

m of vanillin = 0.042mol / 0.05kg = 0.84m

putting all values on the above equation,

ΔTb = (1.22)(0.84) = 1.0248 °C.

Given;

boiling point of ethanol = 78.5 °C.

So the boiling point of vanillin = 78.5 - 1.0248 = 77.47 °C

Hence, the boiling point of a solution of vanillin is 77.47 °C.

Learn more about the boiling point with the help of the given link:

brainly.com/question/1514229

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2 years ago