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exis [7]
3 years ago
14

Two reactants, each having a mass of 50.0 g, react fully in a beaker. What is the total mass of the products in the reaction?

Chemistry
1 answer:
krok68 [10]3 years ago
6 0

Answer:

100g......sieiekeskslapaokdkz

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How does gravity depend on the mass of the two objects
marin [14]

Answer:

Yes

Explanation:

the gravity of an object depends on its mass. that's why the sun has its gravitational pull.

3 0
2 years ago
A 0.211 g sample of carbon dioxide, CO2, has a volume of 560 mL and a pressure of 429 mmHg whats the temperature of the gas in K
SCORPION-xisa [38]

The temperature of the gas sample is 813 K.

<u>Explanation:</u>

We have to use the ideal gas equation to find the temperature of the gas sample.

The ideal gas equation is PV = nRT

Pressure, P = 429 mm Hg = 0.56 atm

Volume, V = 560 mL = 0.56 L

R = gas constant = 0.08205 L atm mol⁻¹K⁻¹

Mass = 0.211 g

Molar mass of carbon di oxide = 44.01 g / mol

Moles, n = $\frac{given mass}{molar mass} = \frac{0.211 g}{44.01 g/mol}

              = 0.0047 mol

Now, we have to plugin the above values in the above equation, we will get the temperature as,

$T= \frac{PV}{nR}

T = $\frac{0.56  \times 0.56}{0.08205 \times 0.0047}

 = 813 K

So the temperature of the gas sample is 813 K.

5 0
4 years ago
CAN SOMEONE PLEASE WRITE ME SHORT STORY FOR THIS. I'LL GIVE YOU BRAINLIEST. I PROMISE. 98 POINTS
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Answer & Explanation:

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6 0
4 years ago
The value of ka for nitrous acid (hno2) at 25 ∘c is 4.5×10−4. what is the value of δg at 25 ∘c when [h+] = 5.9×10−2m , [no2-] =
LuckyWell [14K]
To get the value of ΔG we need to get first the value of ΔG°:

when ΔG° = - R*T*㏑K

when R is constant in KJ = 0.00831 KJ

T is the temperature in Kelvin = 25+273 = 298 K

and K is the equilibrium constant = 4.5 x 10^-4

so by substitution:

∴ ΔG° = - 0.00831 * 298 K * ㏑4.5 x 10^-4

        = -19 KJ

then, we can now get the value of ΔG when:

ΔG = ΔG° - RT*㏑[HNO2]/[H+][NO2]

when ΔG° = -19 KJ

and R is constant in KJ = 0.00831 

and T is the temperature in Kelvin = 298 K

and [HNO2] = 0.21 m & [H+] = 5.9 x 10^-2 & [NO2-] = 6.3 x 10^-4 m  

so, by substitution:

ΔG = -19 KJ - 0.00831 * 298K* ㏑(0.21/5.9x10^-2*6.3 x10^-4 )

       = -40

     
8 0
3 years ago
Which type of cell is larger
Karo-lina-s [1.5K]

Answer: eukaryotic cell

5 0
3 years ago
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