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avanturin [10]
2 years ago
13

I need help please!!

Physics
1 answer:
quester [9]2 years ago
6 0

Answer:

  1. i need help please
  2. need i help please
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Heat in the amount of 100 kJ is transferred directly from a hot reservoir at 1320 K to a cold reservoir at 600 K. Calculate the
Zinaida [17]

Answer:0.0909 kJ/K

Explanation:

Given

Temperature of hot Reservoir T_h=1320 K

Temperature of cold Reservoir T_l=600 K

Heat of 100 kJ is transferred form hot reservoir to cold reservoir

Hot Reservoir is Rejecting heat therefore Q_1=-100 kJ

Heat is added to Reservoir therefore Q_2=100 kJ

Entropy change for system

\Delta s=\frac{Q_1}{T_1}+\frac{Q_2}{T_2}

\Delta s=\frac{-100}{1320}+\frac{100}{600}

\Delta s=-0.0757+0.1666=0.0909 kJ/K

As entropy change is Positive therefore entropy Principle is satisfied

         

4 0
3 years ago
Hi how do i run faster
Andrei [34K]

Answer:

Creatine is a great option , its not gonna help long term running ; but a great boost when you first start the run/jog.

Now to run faster you have to build great endurance and that is done through constant exercise running and stamina work outs such as sports , sprints calistetics etc.

Explanation:

Its not a simple 1 time thing and your suddenly , it takes drive and motivation !

Hope i was able to help you out ! Have a great day :)

7 0
2 years ago
I have a bottle of gas, the bottle can expand and contract. Initially the gas is at 1 kpa of pressure and a volume of 1 Liter, a
drek231 [11]

Answer:

P₂ = 1.22 kPa

Explanation:

This problem can be solved using the equation of state:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

where,

P₁ = initial pressure = 1 KPa

P₂ = final pressure = ?

V₁ = initial Volume = 1 liter

V₂ = final volume = 1.1 liter

T₁ = initial temperature = 290 k

T₂ = final temperature = 390 k

Therefore,

\frac{(1\ kPa)(1\ liter)}{290\ k} =\frac{(P_2)(1.1\ liter)}{390\ k}\\\\P_2= \frac{(1\ kPa)(1\ liter)(390\ k)}{(290\ k)(1.1\ liter)}

<u>P₂ = 1.22 kPa</u>

7 0
2 years ago
Which scenario is in excample of a scientific way to think
vlabodo [156]
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3 years ago
The water is reflecting light, Is this specular or diffuse reflection? explain your answer​
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Yes the answer is true
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