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2 years ago

Which projectile will be visibly affected

Physics

2 answers:

grigory [225]2 years ago

8 0

Gravity is the answer to this question

jonny [76]2 years ago

6 0

Answer:

leaf and a balloon is the correct answer

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What is the correct classification of a mixture in which both a solid and a liquid are visible?

stepan [7]

<span>The answer is a heterogeneous mixture. Mixtures can be homogeneous and heterogeneous. If a solid and a liquid of a mixture cannot be separated and the difference between them is not visible, it is called homogeneous mixture (or solution). If a solid and a liquid of a mixture are visible and can be separated easily, the mixture is called heterogeneous.</span>

7 0

3 years ago

Read 2 more answers

Please help!!! Which is a heterogeneous mixture?

katrin [286]

Answer:

pizza is a heterogeneous mixture.

Explanation:

A heterogeneous mixture is a mixture in which the composition is not uniform throughout the mixture. Vegetable soup is a heterogeneous mixture. Any given spoonful of soup will contain varying amounts of the different vegetables and other components of the soup

5 0

1 year ago

If the caffeine concentration in a particular brand of soda is 2.97 mg/oz, 2.97 mg/oz, drinking how many cans of soda would be l

Ray Of Light [21]

Explanation:

The given data is as follows.

Concentration of caffeine = 2.97 mg/oz

Number of oz in a can = 12 oz

Therefore, the concentration of caffeine in one can is calculated as follows.

= $(12 \times 2.97)$ mg

= 35.64 mg

= $35.64 \times 10^{-3} g$

Since, it is given that lethal dose is 10.0 g. Hence, number of cans are calculated as follows.

No. of cans = $\frac{\text{Lethal dose}}{\text{concentration in one can}}$

= $\frac{10 g}{35.64 \times 10^{-3} g}$

= 280.58

= 281 (approx)

Thus, we can conclude that 281 cans of soda would be lethal.

5 0

3 years ago

Phineas and Ferb are riding their bikes on Main Street. They begin at 11 Mile Rd at

Lady bird [3.3K]

Answer:

1 hour and 25 minutes

Explanation:

hopefully this helps ,, but like WHY phineas and ferb hshjdshjdhdhdbd im so childish

7 0

2 years ago

A block is released from rest, at a height h, and allowed to slide down an inclined plane. There is friction on the plane. At th

GREYUIT [131]

Here the block has two work done on it

1. Work done by gravity

2. Work done by friction force

So here it start from height "h" and then again raise to height hA after compressing the spring

So work done by the gravity is given as

$W_g = m_A g(h - h_A)$

Now work done by the friction force is to be calculated by finding total path length because friction force is a non conservative force and its work depends on total path

$W_f = -(\mu m_A g cos\theta)(\frac{h}{sin\theta} + \frac{h_A}{sin\theta})$

$W_f = -\mu m_A g cot\theta(h + h_A)$

Total work done on it

$W = m_A g(h - h_A) - \mu m_A g cot\theta(h + h_A)$

So answer will be

None of these

7 0

3 years ago

Read 2 more answers