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Ann [662]
2 years ago
11

Why does oil not dissolve in water?

Physics
1 answer:
Fudgin [204]2 years ago
4 0

Answer:

C. Oil is made of non-polar molecules, and water is made of polar molecules.

Explanation:

Non-polar molecules = hydrophobic (water-fearing, doesn’t readily dissolve in water)

Ions & Polar molecules: hydrophilic (water-loving, does readily dissolve in water)

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Question 1 (1 point)
IrinaK [193]
  1.  momentum  
  2. Yes, if the elephant is standing still.
  3. Fullback  
  4. impulse acting on it.  
  5. 2.25 N∙s
  6. A cannon firing.
  7. Inelastic  
  8. it stays the same
  9. When the cue ball contacts the other balls, momentum is transferred causing them to gain momentum and speed.
  10. less than 3 m/s      
<h3><u><em>these are all correct i got an 100%</em></u><em><u> </u></em></h3>
8 0
2 years ago
What was Great Britain’s policy using African Americans during the war
kifflom [539]

Answer:

they were slaves, so they did practically everything anyone didn't do.

Explanation:

btw, which war? or battle?

6 0
3 years ago
Which statements about acceleration are true?
bonufazy [111]
It's definitely not B or C. There are things missing from A and D so we can't narrow it down any farther.
4 0
3 years ago
Which of the following describes the relationship between work and power
Pani-rosa [81]

Answer:

Power is the rate which work is done.

Explanation:

<em>Power</em> is the rate which work is done. Power is measured in watts.

<em>Work</em> is the use of force to move an object. Work is measured in joules

7 0
3 years ago
Physics double pivot question​
andriy [413]

Explanation:

Assuming the wall is frictionless, there are four forces acting on the ladder.

Weight pulling down at the center of the ladder (mg).

Reaction force pushing to the left at the wall (Rw).

Reaction force pushing up at the foot of the ladder (Rf).

Friction force pushing to the right at the foot of the ladder (Ff).

(a) Calculate the reaction force at the wall.

Take the sum of the moments about the foot of the ladder.

∑τ = Iα

Rw (3.0 sin 60°) − mg (1.5 cos 60°) = 0

Rw (3.0 sin 60°) = mg (1.5 cos 60°)

Rw = mg / (2 tan 60°)

Rw = (10 kg) (9.8 m/s²) / (2√3)

Rw = 28 N

(b) State the friction at the foot of the ladder.

Take the sum of the forces in the x direction.

∑F = ma

Ff − Rw = 0

Ff = Rw

Ff = 28 N

(c) State the reaction at the foot of the ladder.

Take the sum of the forces in the y direction.

∑F = ma

Rf − mg = 0

Rf = mg

Rf = 98 N

3 0
3 years ago
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