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topjm [15]
2 years ago
9

A cricketer throws a ball sideways with an initial velocity of 30 m/s. She releases the ball from a height of 1.3m. Calculate ho

w far the ball travels before hitting the ground.
Physics
1 answer:
ioda2 years ago
8 0

Answer:

78.34

Explanation:

1.3/30=78.3m

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6 An object can never have
MAVERICK [17]

Answer:

B

Explanation:

Speed is the magnitude of the velocity vector, so it can never be negative.

6 0
3 years ago
for the same type of atom with 8 protons, 9 neutrons, and 10 electrons, what type of atom or ion is it​
Ilia_Sergeevich [38]

Answer:

O²⁻

Explanation:

Number of protons  = 8

Number of neutrons  = 9

Number of electrons  = 10

What type of atom or ion is it = ?

Solution:

Protons are the positively charged particle in an atom

Neutrons do not carry any charges

Electrons are negatively charged particles

 For this atom, the number of protons helps to identify what specie it is; so this is an oxygen atom.

Now,

     Charge  = Number of protons  - Number of electrons

      Charge  =  8  - 10  = -2

The charge on the atom is -2 and so it is an oxygen ion with -2 charge

 The ion is O²⁻

8 0
2 years ago
Yurem is pulling a wagon across the playground with a force of 10 N. He asks Elianna to help. She agrees and pushes the back of
salantis [7]

Answer:

22 N applied force

Explanation: Since they are both pushing the wagon in the same direction the force adds up.

7 0
3 years ago
Read 2 more answers
A 45 kg bear slides, from rest, 11 m down a lodgepole pine tree, moving with a speed of 5.8 m/s just before hitting the ground.
Viefleur [7K]

Answer:

Explanation:

a )

change  in the gravitational potential energy of the bear-Earth system during the slide  = mgh

= 45 x 9.8 x 11

= 4851 J

b )

kinetic energy of bear just before hitting the ground

= 1/2 m v²

= .5 x 45 x 5.8²

= 756.9 J

c ) If  the average frictional force that acts on the sliding bear be F

negative work done by friction

= F x 11 J

then ,

4851 J -  F x 11 =  756.9 J

F x 11 = 4851 J -   756.9 J

= 4094.1 J

F = 4094.1 / 11

= 372.2 N  

4 0
3 years ago
Two charges of equal magnitude Q are held a distance d apart. Consider only points on the line passing through both charges.For
Burka [1]

Answer:

A

Explanation:

6 0
3 years ago
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