Please tell me the answer of this question, first person to answer will be marked brainlist

A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f

a_sh-v [17]

Answer:

$m_{H_2O}=39.0g$

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

$\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})$

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

$m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g$

Best regards.

8 0

3 years ago

For each situation below, state whether water will move into the cell, move out of the cell, or stay the same.

Firdavs [7]

Water moves from an area of higher water potential (aka. "more water" in simple language) to an area of lower water potential (aka. "less water" in simple language).

For A, cells in carrots have water stored in their cytoplasm, where many soluble substances may be found (e.g. sodium ions). On the other hand, pure water has no other soluble substances other than the water molecules (I.e. H2O). Pure water will thus have a higher water potential as compared to the water in carrot cells, and so, water will move from pure water into the carrot cells via osmosis down a concentration gradient.

B. Corn syrup is water that has high concentrations of sugars, thus it is very likely to have a lower water potential than the cells of carrots. Water will move from within the cells of carrots and out to the corn syrup, down a concentration gradient.

C. The water in carrot cells will stay the same, since carrot cells have the same water potential as the surrounding solution which has the same water potential as cytoplasm.

Hope this helps! :)

8 0

3 years ago

One hundred million copper atoms are arranged in a line. which is a reasonable estimate for the length of this line?

Alex777 [14]

10^-8 cm/atom times 10^8 atoms = 1 cm

6 0

3 years ago

Read 2 more answers

What is the electron structure of a sodium atom?

Irina-Kira [14]

Answer:

1s2 2s2 2p6 3s1

Explanation:

All the elements in the periodic table, has an atomic number. This number tell us different things, such as number of protons, position in the periodic table among others.

One of the things that tell us the atomic number is the electron structure.

First, all elements begins always with 1s. This is because the first number indicates number of energy level which is in. This tell us, the period of the periodic table is the element, the s, is the type of orbital which the electrons are located. the s orbytal can only have 2 electrons max, and with the increasement of the atomic number, this electrons also increase.

Therefore for an element like Helium, (atomic number = 2) means that we have to begin with the 1s and put 2 electrons, to complete the atomic number. In this case, it would be 1s2.

When we surpass this number, we use another energy level, in this case, 2, and begin again with orbytal s. Then, when we surpass 2s2, we use now another orbytal, which is p. This is because we have more elements in the second period of the table, so we need another kind of energy levels to carry all the electrons. orbytal p can carry up to 6 electrons max, so for an element like Florine (Atomic number = 9), it's structure would be 1s2 2s2 2p5. As you can count the electrons, we have 2 + 2 + 5 = 9, we complete the atomic numbers and the electrons would be, the numbers of electrons located in the last energy level, in this case, the 2s and 2p, and it would be 7 electrons.

Now after this explanation, in the case of sodium (Na), the atomic number of sodium is 11, therefore, we need to count til 11 so:

[Na] = 1s2 2s2 2p6 3s1

As you can see, sodium is the first element of period 3 of the table, and we begin with the energy level 3. In your case it would be the last option you put.

8 0

3 years ago

The gas arsine, AsH3, decomposes as follows: In an experiment at a certain temperature, pure AsH3(g) was placed in an empty, rig

bazaltina [42]

The equilibrium pressure of $H_{2}$ is 288 torr. and $K_{p}$ for this reaction is 0.786 atm.

from the reaction:- $2AsH_{3}$ ⇄ $2As + 3H_{2}$

initial concentration 392 torr. 0

at equilibrium. 392 - $2x$ . $3x$

and the final pressure in the flask = 488 torr.

Hence,

$( 392 - 2x ) + 3x = 488\\ x = 488-392\\x = 96 torr.$

The partial pressure of $H_{2}$ is 3 × 96 = 288 torr.

and $AsH_{3}$ is 392 - ( 2 × 96 ) = 392 - 192 = 200 torr.

Now, to find $K_{p}$ for this reaction, we will use $K_{p} = \frac{(P_{H_{2} })^{2} }{( P_{AsH_{3} } )^{2}}$

putting all the values, we get,

$K_{p} = \frac{(288)^{3} }{(200)^{2} }$

= 597.1968 torr.

= 0.786 atm. ( 1 atm = 760 torr. )

what do you mean by equilibrium?

Equilibrium in chemistry is the phase that exists when a chemical reaction and its opposite reaction happen at the same rates. This word's Latin origin dates back to the prefix aequi-, which means equal, and lbra, that indicates scale or balance.

Learn more about equilibrium reaction here:-

brainly.com/question/15118952

#SPJ4

3 0

2 years ago