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Masja [62]
3 years ago
6

One hundred million copper atoms are arranged in a line. which is a reasonable estimate for the length of this line?

Chemistry
2 answers:
Alex777 [14]3 years ago
6 0
10^-8 cm/atom times 10^8 atoms = 1 cm
Vedmedyk [2.9K]3 years ago
4 0

Answer:10^-8 cm/atom times 10^8 atoms = 1cm

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A group of students working in a high school chemistry lab believe they have discovered a new element! How exciting? Upon furthe
spayn [35]

Answer:

Explanation:

Information given about the element:

Number of protons = 74

Number of neutrons = 110

For the atomic number:

Neutral atoms such as this one would have their atomic number to be the same with their number of electrons and protons:

     atomic number = number of protons = number of electrons

The atomic number would therefore be 74

For the mass number:

The mass of an atom is centrally concentrated within the tiny nucleus. The mass number is the sum of protons and neutrons in an atom. Protons and neutrons are nuclear particles and are called nucleons:

     Mass number = number of protons + number of neutrons = 74+110=184

Is this a new element?

From the peroidic table, tungsten(W) perfectly fits this description of the atom. It has an atomic number of 74 and a mass number of approximately 184. The element is not a new element.

Is it solid, liquid, or gas?

The element is a hard metallic solid. It is a classified as a transition metal on the periodic table. Transition metals have very unique metals and are mostly solids.

4 0
3 years ago
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A piece of copper absorbs 5000 J of energy and undergoes a temperature change from 100 °C to 200 °C. What is the mass of the pie
irakobra [83]

Answer:

B.) 129.9 grams

Explanation:

To find the mass, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature (°C)

The specific heat of copper is 0.385 J/g°C. Knowing this, you can plug the given values into the equation and simplify to isolate "m".

Q = mcΔT                                                            <----- Equation

5000 J = m(0.385 J/g°C)(200 °C - 100 °C)        <----- Insert values

5000 J = m(0.385 J/g°C)(100)                            <----- Subtract

5000 J = m(38.5)                                                <----- Multiply 0.385 and 100

129.9 = m                                                             <----- Divide both sides by 38.5

8 0
1 year ago
What other product occurs when ac-222 releases an alpha particle?
irga5000 [103]
There is fr-218

hope this did the job, have a nice rest of your day!!

3 0
3 years ago
Whats the name for K2SO4??
emmasim [6.3K]
POTASSIUM SULFATE hope this helps
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