Answer:
158
Explanation:
The input is 6.185/10.000 = 0.6185 of the full-scale of the A/D converter. If a 10V input is represented by a register value of 255, then the expected register value for this input is about ...
0.6185·255 = 157.7175 ≈ 158
_____
In hexadecimal, that is 9E.
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Carbon is not used as semiconductor it has 4 valence electrons in it valence shell but the energy gap is very small it will conduct electricity even at room temperature ,the size of carbon is very small .
19 vans are needed. 9 for the boys and 10 for the girls
If you only can have 8 students in each van you need to divide each number by 8. So 72/8 is 9 for the boys and 75/8 is 9.4 since this is over 9 you’ll need 10 for the girls.
Answer:
(a) 185.1002 lbm/min
(b) 7125.12 Btu/min
(c) 0.42
Explanation:
Here we have;
= 6
γ = 1.4 for air
T₁ = 460 R = 255.56 K
T₃ = 700 R = 388.89 K
1 ton of refrigeration capacity = 3.52 kWh = 0.98 W
∴ 15 ton = 15×3.52 = 52.8 kW/h
= 189910.0534716 kJ/h = 3165.1676 kJ/min
T₂ = 1.669 × 460 = 767.515 R = 426.4 K
Refrigeration effect per kg = 1 × × (T₃ - T₂) = 1.005 × (700 - 767.515) = 67.85 = 37.7 kJ/kg
83.96 kg/min = 185.1002 lbm/min
(b)
T₄ = T₃×1.669 = 700×1.669 = 1167.96 °R = 648.9 K
= 21925.83 kJ/min
= 14408.4 kJ/min
= 21925.83 - 14408.4 = 7517.43 kJ/min
1 kW = 56.87 Btu/min
Therefore;
125.29 kW = 7125.12 Btu/min
(c) The coefficient of performance (COP), is given by the relation;