3 years ago

MCQ : What are the main the constituents of acid rains?

Engineering

2 answers:

IrinaVladis [17]3 years ago

4 0

Answer:

c is correct

Explanation:

nexus9112 [7]3 years ago

3 0

Answer:

a. Nitrogen Oxide

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The purpose of pasteurizing milk is to

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Answer:

i think it c

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Which is the better measure of computer system performance—a benchmark, such as SPECINT; or a processor speed measure, such as G

Vesna [10]

Answer:

A benchmark

Explanation:

Most times a benchmark serves as the better measure when assessing a computer's performance, this is because CPU speeds can only evaluate an aspect of a computer's performance whereas a benchmark offers the advantage of measuring all the aspects of a computer's performance for a specific type of computing problem.

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3 years ago

How do I get my son to do his work?

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Answer:

Explanation:

Reward him if he does his homework/work

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A sample of municipal sewage is diluted to 1% by volume prior to running a BOD5 analysis. After 5 days the oxygen consumption is

liberstina [14]

Answer:

BOD5 = 200 mg/L

Explanation:

given data

diluted = 1% = 0.01

time = 5 day

oxygen consumption = 2.00 mg · L−1

solution

we get here BOD5 that is BOD after 5 day

and here total volume is 100% = 1

so dilution factor is $\frac{100}{1}$ = 100

so BOD5 is

BOD5 = oxygen consumption × dilution factor

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3 years ago

Water enters a tank from two pipes, one with a flow rate of 0.3 kg/s and the other with a flow rate of 0.1 kg / s. The tank has

stiks02 [169]

Answer:

total amount of water after 2 min will be 84.4 kg/s

Explanation:

Given data:

one tank inflow = 0.1 kg/s

2nd tank inflow = 0.3 kg/s

3rd tank outflow = 0.03 kg/s

Total net inflow in tank is = 0.3 +0.1 =0.4 kg/s

From third point, outflow is 0.03 kg/s

Therefore, resultant in- flow = 0.4 - 0.03

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In 2 min ( 2*60 sec), total inflow in tank is 0.37*60*2 = 44.4 kg

So, total amount of water after 2 min will be = 40+44.4 = 84.4 kg

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3 years ago