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vlada-n [284]
3 years ago
7

MSG (monosodium glutamate has the following composition by mass: 51% C; 4.77 % H, 37.8 % 0; 8.29 % N and 13.60 % Na. What is the

molecular formula if its molar mass is 169 g​
Chemistry
1 answer:
amm18123 years ago
7 0

Following the composition by mass, the molecular formula of monosodium glutamate would be C_7H_8O_4NNa

The empirical formula can first be derived such that:

C = 51/12             = 4.25

H = 4.778/1           = 4.77

O = 37.8/16       = 2.36

N = 8.29/14       = 0.59

Na = 13.60/23      = 0.59

Dividing by the smallest (0.59):

C = 7

H = 8

O = 4

N = 1

Na = 1

Hence, the empirical formula would be C_7H_8O_4NNa

Molar mass of empirical formula = 12x7 + 8x1 + 16x4 + 14 + 23

                                                         = 195

Recall that: , (C_7H_8O_4NNa)n = molecular formula

                                   Where n = molar mass/empirical formular mass

Molar mass/empirical formular mass = 169/195

                                                       = 0.87

                                                          ≈ 1

Thus, (C_7H_8O_4NNa) x 1 = C_7H_8O_4NNa

More on molecular formula calculation can be found here: brainly.com/question/21629131

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Answer:

The answer to your question is below

Explanation:

To solve this problem use the general formulas for Alkanes, Alkenes, and Alkynes.

Alkanes           Cn H(2n + 2)

Alkenes           Cn H (2n)              "n" is the number of Carbons

Alkynes            Cn H (2n - 2)

a) CH₄             C₁ H 2(1) +2   = C₁H₂ + ₂ = CH₄       Alkane

b) C₂H₄            C₂ H₂(₂)                                           Alkene

c) C₃H₆             C(₃) H₂ (₃)                                        Alkene

d) C₂H₂            C₂ H₂(₂) - 2  = C₂H₄ - ₂ = C₂H₂        Alkyne

e) C₁₀H₂₂          C₁₀ H₂(₁₁)                                          Alkene

5 0
3 years ago
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