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3 years ago

What is the ground-state electron configuration of a neutral atom of cobalt?

Chemistry

1 answer:

Andre45 [30]3 years ago

8 0

4d7 , 3s2 will be the valence shell electronic configuration of a neutral atom of cobalt!

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Find the potentials of the following electrochemical cell:

melomori [17]

Answer: 0.18 V

Explanation:-

$Cd/Cd^{2+}(0.10M)//Ni^{2+}(0.50M)?Ni$

Here Cd undergoes oxidation by loss of electrons, thus act as anode. nickel undergoes reduction by gain of electrons and thus act as cathode.

$E^0_(Cd^{2+}/Cd)$ =-0.40V[/tex]

$E^0_(Ni^{2+}/Ni)$ =-0.24V[/tex]

$Cd+Ni^{2+}\rightarrow Cd^{2+}+Ni$

Here Cd undergoes oxidation by loss of electrons, thus act as anode. nickel undergoes reduction by gain of electrons and thus act as cathode.

$E^0=E^0_{cathode}- E^0_{anode}$

Where both $E^0$ are standard reduction potentials.

$E^0=E^0_{[Ni^{2+}/Ni]}- E^0_{[Cd^{2+}/Cd]}$

$E^0=-0.24-(-0.40)=0.16V$

Using Nernst equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Cd^{2+}]}{[Ni^{2+]}$

where,

n = number of electrons in oxidation-reduction reaction = 2

$E^o_{cell}$ = standard electrode potential = 0.16 V

$E_{cell}=0.16-\frac{0.0592}{2}\log \frac{[0.10]}{[0.5]}$

$E_{cell}=0.18V$

Thus the potential of the following electrochemical cell is 0.18 V.

6 0

3 years ago

If a snack cake contains 450 food calories and Carla

Oksana_A [137]

Answer:

9/10hr

Explanation:

From the question given:

Carla was able to burn 250 calories by running for one-half (1/2)hr.

Therefore, Carla will burn 450calories by running for = (450x1/2) /250 = 225/250 = 9/10hr

8 0

3 years ago

The valencies of metal a,band c are 1,2,3respectively what is the formula of hydroxide of a

Luba_88 [7]

The formula of metal hydroxides for

A) metal A = A(OH)

B) metal B = B(OH)₂

C) metal C = C(OH)₃

<h3>What are hydroxides?</h3>

When a metal's oxide combines with water, a hydroxide is created.

The general formula of hydroxide is:

M(OH)ₙ

where n is the valency of metal.

OH has a valency of -1

A) The formula of hydroxide of metal A:

The valency of metal A is 1

This means, here, n = 1

Therefore, the metal hydroxide formula will be = A(OH)

B) The formula of hydroxide of metal B:

The valency of metal B is 2

This means, here, n = 2

Therefore, the metal hydroxide formula will be = B(OH)₂

C) The formula of hydroxide of metal C:

The valency of metal C is 3

This means, here, n = 3

Therefore, the metal hydroxide formula will be = C(OH)₃

Learn more about formula of hydroxides here:

brainly.com/question/23442676

#SPJ4

6 0

2 years ago

In protein synthesis, how many nitrogenous bases code for a single amino acid?

steposvetlana [31]

3 nitrogenous bases code a single amino acid , and it is called codon.

8 0

3 years ago

HgO➡️Hg➡️O(subscript 2)

sammy [17]

So in order to answer this we need the number of moles of oxygen and the right stoichiometry.
The balanced reaction should be 2HgO --> 2Hg + O2, therefore 2 moles of mercury are produced for every one mole of oxygen gas. Since we have the mass of O2 we can calculate the moles as moles = mass/RMM where RMM is the relative molecular mass of O2, which is 32 g/mol. Therefore the number of moles = 125/16 = 3.9 mol.
Since 2 moles of Hg are produced for every one mole of O2, the number of moles of Hg = 3.9*2 = 7.8 mol.

8 0

3 years ago