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2 years ago

5

I don't understand this question can someone help me with this please, please explain!! and thank you for the help!! If u dont k

now try your best. Please do it quick, please do all :D

1 answer:

mestny [16]2 years ago

6 0

Answer:

#1=d

#2=a

Step-by-step explanation:

i am not sure about #1 though good luck

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What is the value of y in this triangle?

xeze [42]

Answer: y=36 degrees

Step-by-step explanation: the exterior angle of a triangle is equal to the sum of the two remote interior angles of a triangle. using this, you can subtract 98 from 134 degrees to find your answer. 134-98 is 36 degrees. Hope this helps :)

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2 years ago

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Find the 9th term of the geometric sequence 5, -25, 125, ...

arlik [135]

Answer:

Step-by-step explanation:

a = 5

r = -5

n = 9

t_9 = a r^(n - 1)

t_9 = (-1)^n*5 (-5) ^ 8

t_9 = (-1)^9 * 5 * (-5) ^8

t_9 = -1 ( 1953125)

t_9 = - 1953125

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3 years ago

Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

<em><u>Therefore, the two roots are:</u></em>

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

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3 years ago

Can u use the distributive property to simplify 2(n - 6) if so what

OverLord2011 [107]

2 x (n - 6)
(2 x n - 2 x 6)
(2n - 2 x 6)
2n - 12

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3 years ago

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A right triangle has an area of 50 square inches. If the triangle is an isosceles triangle, what are the lengths of the legs of

Fed [463]

<span>If this is an isosceles triangle, then it has two 45 degree angles corresponding to two legs of equal length. Orient the base of this triangle so that it's horizontal, and represent its length by b. Let h represent the height of the triangle. Then the area of this right triangle is 50 square inches = (1/2)(b)(h), or A = (b/2)h = 50 in^2.

Due to the 45 degree angles, the height of this triangle is equal to half the base, or h = b/2. Thus, (b/2)h = 50 becomes (b/2)(b/2) = 50, or b^2=200. Thus, b = 10sqrt(2), and h=(1/2)(10 sqrt(2)), or h = 5sqrt(2).

The length of one of the legs is the sqrt of [5sqrt(2)]^2+[5sqrt(2)]^2, or

sqrt(25(2)+25(2)) = sqrt(100) = 10.

</span>

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3 years ago