2 years ago

It took 50 joules to push a crate 2.5 meters. With what force was the crate pushed?

1 answer:

Inga [223]2 years ago

7 0

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rosijanka [135]

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2 years ago

goblinko [34]

Answer:

d = 2083.33 m

Explanation:

Given that,

Acceleration of the train, a = 0.15 m/s²

The initial speed of the car, u = 0\

Final velocity, v = 25 m/s

We need to find the minimum distance covered by the train. Let it is d. Using third equation of kinematics as follows :

$v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(25)^2-0}{2\times 0.15}\\\\d=2083.33\ m$

So, the minimum distance is 2083.33 m

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3 years ago

zhannawk [14.2K]

Answer:

-48,800,000 or 71,200,000

Explanation:

subtraction or addition :D

I hope I helpped (ㆁωㆁ)

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2 years ago