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m_a_m_a [10]
2 years ago
10

It took 50 joules to push a crate 2.5 meters. With what force was the crate pushed?

Physics
1 answer:
Inga [223]2 years ago
7 0

It took 50 joules to push a crate 2.5 meters. With what force was the crate pushed?

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An object is at rest on the ground. The object experiences a downward gravitational force from Earth. Which of the following pre
Montano1993 [528]

Answer:

A) and B) are correct.

Explanation:

If the object is at rest, it means that no net force is exerted on it.

As the object experiences a downward gravitational force from Earth, in order to be at rest, it must experience an upward force with the same magnitude as the gravitational force on the object.

This force is supplied by the normal force, which can adopt any value in order to meet the condition imposed by Newton´s 2nd Law, and is always perpendicular to the surface on which the object is placed (in this case, the ground).

At a molecular level, this normal force is supplied by the bonded molecules of the ground that behave like small springs being compressed by the molecules of the object, exerting an upward restoring force upward on them.

So, the statements A) and B) are true.

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3 years ago
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A current of 12 amps is measured in a circuit with a total resistance of 9.0 ohms. What is the size of the voltage source that s
Lynna [10]
A. 108 volts is the answer.
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3 years ago
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A war wolf is a device used during the middle ages to assault fortifications with large rocks. A simple trebuchet is constructed
Katarina [22]

Answer:v=41.23 m/s

Explanation:

Given

mass of heavy object m_1=52 kg

distance of m_1 from the axle r_1=14 cm

mass of rock m_2=123 gm

Length of rod =4.1 m

distance of m_2 from axle r_2=4.1-0.14=3.96 m

Net torque acting is

T_{net}=m_1gr_1-m_2gr_2

T_{net}=52\times 0.14\times g-0.123\times 3.96\times g

T_{net}=6.793\times 9.8

T_{net}=66.57 N-m

Work done by T_{net} is converted to rock kinetic Energy

thus

T_{net}\times \theta =\frac{mv^2}{2}

Where \theta =angle\ turned =\frac{\pi }{2}

v= velocity\ at\ launch

66.57\times \frac{\pi }{2}=\frac{0.123\times v^2}{2}

v^2=66.57\times \pi

v=\sqrt{1700.511}

v=41.23 m/s

3 0
4 years ago
What is the acceleration of a car that goes from 40 m/s to 80 m/s in 2s?
Law Incorporation [45]

Answer:

2

Explanation:

pls brainlyest i need it

3 0
2 years ago
Help me with this please
creativ13 [48]

Answer:

i dont understand, can you put it in word form please.

Explanation:

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