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antoniya [11.8K]
3 years ago
15

A sled is pulled up to the top of a hill. At thetop of the hill the sled is released from rest and allowed to coastdown the hill

. At the bottom of the hill the sled has a speedv and a kinetic energy E ( the energy due to the sled'smotion).The sled is pulled up a steeper hill ofthe same height as the hill described above. Howe will thevelocity of the sled at the bottom of the hill (after it has sliddown) compare to that of the sled at the bottom of the originalhill?a. the speed at the bottom is greater for the steeperhillb. the speed at the bottom is the same for both hills.c. the speed at the bottom is greater for the orignal hillbecause the sled travels further.d. there is not enough information given to say which speed atthe bottom is fastere. none of the above
Physics
1 answer:
Stolb23 [73]3 years ago
8 0

Answer:

a.) the speed at the bottom is greater for the steeperhill

Explanation:

since the energy at the bottom of the steeper hilis greater

mgh =\frac{1}{mv^2}

As we can see from above that v is higher when h ishigher.

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action and reaction are equal in magnitude and opposite direction then why they don't balance each other
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a bubble of air of volume 1cm^3 is released by a deep sea diver at a depth where the pressure is 4.0 atmospheres. assuming its t
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Answer:

hope this helps!

Explanation:

Volume of the air bubble, V1=1.0cm3=1.0×10−6m3

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The pressure on the surface of the lake: P2=1atm=1×1.103×105Pa 

The pressure at the depth of 40 m: P1=1atm+dρg

Where,

ρ is the density of water =103kg/m3

g is the acceleration due to gravity =9.8m/s2

∴P1=1.103×105+40×103×9.8=493300Pa

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V2=

8 0
3 years ago
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2 years ago
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