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antoniya [11.8K]
3 years ago
15

A sled is pulled up to the top of a hill. At thetop of the hill the sled is released from rest and allowed to coastdown the hill

. At the bottom of the hill the sled has a speedv and a kinetic energy E ( the energy due to the sled'smotion).The sled is pulled up a steeper hill ofthe same height as the hill described above. Howe will thevelocity of the sled at the bottom of the hill (after it has sliddown) compare to that of the sled at the bottom of the originalhill?a. the speed at the bottom is greater for the steeperhillb. the speed at the bottom is the same for both hills.c. the speed at the bottom is greater for the orignal hillbecause the sled travels further.d. there is not enough information given to say which speed atthe bottom is fastere. none of the above
Physics
1 answer:
Stolb23 [73]3 years ago
8 0

Answer:

a.) the speed at the bottom is greater for the steeperhill

Explanation:

since the energy at the bottom of the steeper hilis greater

mgh =\frac{1}{mv^2}

As we can see from above that v is higher when h ishigher.

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A discus thrower turns with angular acceleration of 50 rad/s2, moving the discus in a circle of radius 0.80m. Find the radial an
anyanavicka [17]

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The value of tangential acceleration \alpha_{t} =  40 \frac{m}{s^{2} }

The value of radial acceleration \alpha_{r} = 80 \frac{m}{s^{2} }

Explanation:

Angular acceleration = 50 \frac{rad}{s^{2} }

Radius of the disk = 0.8 m

Angular velocity = 10 \frac{rad}{s}

We know that tangential acceleration is given by the formula \alpha_{t} = r \alpha

Where r =  radius of the disk

\alpha = angular acceleration

⇒ \alpha_{t} = 0.8 × 50

⇒ \alpha_{t} = 40 \frac{m}{s^{2} }

This is the value of tangential acceleration.

Radial acceleration is given by

\alpha_{r} = \frac{V^{2} }{r}

Where V = velocity of the disk = r \omega

⇒ V = 0.8 × 10

⇒ V = 8 \frac{m}{s}

Radial acceleration

\alpha_{r} = \frac{8^{2} }{0.8}

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7 0
4 years ago
What velocity will a freefalling object have after falling 80 meters
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Answer:

129.96

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Why is the weight of a free falling body zero? It is not, an object in free fall will still have a weight, governed by the equation W = mg, where W is the object's weight, m is the object's mass, and g is acceleration due to gravity. Weight, however, has no effect on an objects free falling speed, two identically shaped objects weighing a different amount will hit the ground at the same time.

Hope this helps!! If so please mark brainliest and rate/heart to help my account if it did!!

6 0
3 years ago
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