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Mamont248 [21]
2 years ago
15

What is the density of a cube that has a mass of 3.75 g and a volume of 3 mL?

Physics
1 answer:
valina [46]2 years ago
6 0

Answer:

\displaystyle \rho=1.25\ g/ml

Explanation:

<u>Density </u>

The density of a substance is the mass per unit volume. The density varies with temperature and pressure.

The formula to calculate the density of a substance of mass (m) and volume (V) is:

\displaystyle \rho=\frac{m}{V}

The cube has a mass of m=3.75 g and a volume of V=3 ml, thus the density is:

\displaystyle \rho=\frac{3.75\ g}{3\ ml}

\boxed{\displaystyle \rho=1.25\ g/ml}

Since 1 kg=1000 mg and 1 lt = 1000 ml, the density has the same value but with different units:

\displaystyle \rho=1.25\ kg/l

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Given 4.8 moles of a gas at 37 degrees Celsius and at 792 torr, what is the volume of the gas? (The ideal gas constant is 0.0821
Anastaziya [24]

Answer:

1.17 x 10^2 L

Explanation:

We can find the volume of the gas by using the ideal gas law:

pV=nRT

where we have:

p=792 Torr \cdot \frac{1 atm}{760 Torr} = 1.04 atm is the pressure

V is the volume

n = 4.8 mol is the number of moles

R = 0.0821 L · atm/mol · K is the ideal gas constant

T=37^{\circ}+273 =310 K is the temperature

Solving the equation for V, we find the volume

V=\frac{nRT}{p}=\frac{(4.8 mol)(0.0821 L atm/mol K)(310 K)}{1.04 atm}=117.5 L = 1.17\cdot 10^2 L

4 0
3 years ago
Which of the following is not a synthesis reaction?
Nastasia [14]
C is the awnser because c is single replacement
6 0
3 years ago
A steel drill making 180 rpm is used to drill a hole in a block of steel. The mass of the steel block and the drill is 180 g. If
SVETLANKA909090 [29]

Answer:

a) 37.8 W

b) 2 Nm

Explanation:

180 g = 0.18 kg

We can also convert 180 revolution per minute to standard angular velocity unit knowing that each revolution is 2π and 1 minute equals to 60 seconds

180 rpm = 180*2π/60 = 18.85 rad/s

We can use the heat specific equation to find the rate of heat exchange of the steel drill and block:

\dot{E} = mc\Delta \dot{t} = 0.18*420*0.5 = 37.8 J/s

Since the entire mechanical work is used up in producing heat, we can conclude that the rate of work is also 37.8 J/s, or 37.8 W

The torque T required to drill can be calculated using the work equation

E = T\theta

\dot{E} = T\dot{\theta} = T\omega

T = \frac{\dot{E}}{\omega} = \frac{37.8}{18.85} = 2 Nm

7 0
3 years ago
A point charge of -4.28 pC is fixed on the y-axis, 2.79 mm from the origin. What is the electric field produced by this charge a
makkiz [27]

Answer:

E = (-3.61^i+1.02^j) N/C

magnitude E = 3.75N/C

Explanation:

In order to calculate the electric field at the point P, you use the following formula, which takes into account the components of the electric field vector:

\vec{E}=-k\frac{q}{r^2}cos\theta\ \hat{i}+k\frac{q}{r^2}sin\theta\ \hat{j}\\\\\vec{E}=k\frac{q^2}{r}[-cos\theta\ \hat{i}+sin\theta\ \hat{j}]              (1)

Where the minus sign means that the electric field point to the charge.

k: Coulomb's constant = 8.98*10^9Nm^2/C^2

q = -4.28 pC = -4.28*10^-12C

r: distance to the charge from the point P

The point P is at the point (0,9.83mm)

θ: angle between the electric field vector and the x-axis

The angle is calculated as follow:

\theta=tan^{-1}(\frac{2.79mm}{9.83mm})=74.15\°

The distance r is:

r=\sqrt{(2.79mm)^2+(9.83mm)^2}=10.21mm=10.21*10^{-3}m

You replace the values of all parameters in the equation (1):

\vec{E}=(8.98*10^9Nm^2/C^2)\frac{4.28*10^{-12}C}{(10.21*10^{-3}m)}[-cos(15.84\°)\hat{i}+sin(15.84\°)\hat{j}]\\\\\vec{E}=(-3.61\hat{i}+1.02\hat{j})\frac{N}{C}\\\\|\vec{E}|=\sqrt{(3.61)^2+(1.02)^2}\frac{N}{C}=3.75\frac{N}{C}

The electric field is E = (-3.61^i+1.02^j) N/C with a a magnitude of 3.75N/C

8 0
3 years ago
A car accelerates uniformly from rest to a speed of 6.6 m/s in 6.5 s. Find the acceleration the car presents during this time?
Art [367]

Answer:

1.02 m/s²

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 0 m/s

Final velocity (v) = 6.6 m/s

Time (t) = 6.5 s

Acceleration (a) =.?

Acceleration can simply be defined as the change of velocity with time. Mathematically, it can be expressed as:

a = (v – u) / t

Where:

a is the acceleration.

v is the final velocity.

u is the initial velocity.

t is the time.

With the above formula, we can obtain the acceleration of the car as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 6.6 m/s

Time (t) = 6.5 s

Acceleration (a) =.?

a = (v – u) / t

a = (6.6 – 0) / 6.5

a = 6.6 / 6.5

a = 1.02 m/s²

Therefore, the acceleration of the car is 1.02 m/s²

3 0
3 years ago
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