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Mamont248 [21]
3 years ago
15

What is the density of a cube that has a mass of 3.75 g and a volume of 3 mL?

Physics
1 answer:
valina [46]3 years ago
6 0

Answer:

\displaystyle \rho=1.25\ g/ml

Explanation:

<u>Density </u>

The density of a substance is the mass per unit volume. The density varies with temperature and pressure.

The formula to calculate the density of a substance of mass (m) and volume (V) is:

\displaystyle \rho=\frac{m}{V}

The cube has a mass of m=3.75 g and a volume of V=3 ml, thus the density is:

\displaystyle \rho=\frac{3.75\ g}{3\ ml}

\boxed{\displaystyle \rho=1.25\ g/ml}

Since 1 kg=1000 mg and 1 lt = 1000 ml, the density has the same value but with different units:

\displaystyle \rho=1.25\ kg/l

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Answer:

Acceleration = 2.35 m/s^{2}

Speed = 8.67 m/s

Explanation:

The coefficient of friction , u =0.3

The angle of incline = 30°

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weight along the incline = mg cos60° = \frac{mg}{2} = 0.5 mg

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Net force acting on the weight = (0.5 - 0.26) mg = 0.24 mg

Acceleration = \frac{net force}{mass} = 0.24 g = 2.35 m/s^{2}

The height of incline = 8 m

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4 years ago
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Under the reasonable assumption that the brick has more mass than the feather, the brick experiences a greater force of air friction.

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Since acceleration for each object is zero, the sum of the force acting on each of those objects must also be zero.

Since the only forces acting on the objects are gravity and the force of air friction, in order to zero out, <u>the force of air friction must be equal in magnitude and opposite in direction to the force of gravity</u>.

Recall that near the surface of the earth, F_{gravity}=mg, so <u>the Force of Gravity acting on an object is directly proportional to the object's mass</u>.  <em>(A similar argument could be made even if this were not taking place on the surface of the earth, so long as the objects were the same distance from the object providing gravitational influence).</em>

If the masses of the objects are different, <u>the object with the greater mass will experience</u> a larger force of gravity, and hence <u>a larger force of air friction</u> at terminal velocity.  

Under the reasonable assumption that the brick has more mass than the feather, the brick experiences a greater force of air friction.

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