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dalvyx [7]
3 years ago
14

Plz help. find the solution for: 9-3 | x-2 | = 4 will give brainliest.

Mathematics
2 answers:
kkurt [141]3 years ago
8 0
I think the answer is x= 11/3, 1/3



I hope this helps
meriva3 years ago
7 0

answer:

x=1/3

x=11/3

STEP 1:

Rearrange this Absolute Value Equation

Absolute value equalitiy entered

-3|x-2|+9 = 4

Another term is moved / added to the right hand side.

To make the absolute value term positive, both sides are multiplied by (-1).

3|x-2| = 5

STEP 2:

Clear the Absolute Value Bars

Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.

The Absolute Value term is 3|x-2|

For the Negative case we'll use -3(x-2)

For the Positive case we'll use 3(x-2)

STEP 3:

Solve the Negative Case

-3(x-2) = 5

Multiply

-3x+6 = 5

Rearrange and Add up

-3x = -1

Divide both sides by 3

-x = -(1/3)

Multiply both sides by(-1)

x = (1/3)

Which is the solution for the Negative Case

STEP 4:

Solve the Positive Case

3(x-2) = 5

Multiply

3x-6 = 5

Rearrange and Add up

3x = 11

Divide both sides by 3

x = (11/3)

Which is the solution for the Positive Case

giving us  x=1/3 or x=11/3

allso if u can i need help with a thing so plese help, i would aprestiate it

brainly.com/question/25340824

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mafiozo [28]

Answer:

(a) The significance level of the test is 0.002.

(b) The power of the test is 0.3487.

Step-by-step explanation:

We are given that a coin is thrown independently 10 times to test the hypothesis that the probability of heads is 0.5 versus the alternative that the probability is not 0.5.

The test rejects the null hypothesis if either 0 or 10 heads are observed.

Let p = <u><em>probability of obtaining head.</em></u>

So, Null Hypothesis, H_0 : p = 0.5

Alternate Hypothesis, H_A : p \neq 0.5

(a) The significance level of the test which is represented by \alpha is the probability of Type I error.

Type I error states the probability of rejecting the null hypothesis given the fact that the null hypothesis is true.

Here, the probability of rejecting the null hypothesis means we obtain the probability of observing either 0 or 10 heads, that is;

            P(Type I error) = \alpha

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P(X = 0/H_0 is true) + P(X = 10/H_0 is true) = \alpha

\binom{10}{0}\times 0.5^{0} \times (1-0.5)^{10-0}  +\binom{10}{10}\times 0.5^{10} \times (1-0.5)^{10-10}  = \alpha

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(b) It is stated that the probability of heads is 0.1, and we have to find the power of the test.

Here the Type II error is used which states the probability of accepting the null hypothesis given the fact that the null hypothesis is false.

Also, the power of the test is represented by (1 - \beta).

So, here, X ~ Binom(n = 10, p = 0.1)

1-\beta = P(X = 0/H_0 is true) + P(X = 10/H_0 is true)

1-\beta = \binom{10}{0}\times 0.1^{0} \times (1-0.1)^{10-0}  +\binom{10}{10}\times 0.1^{10} \times (1-0.1)^{10-10}  

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1-\beta = 0.3487

Hence, the power of the test is 0.3487.

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Explanation:

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Let z also be adjacent and supplementary to x. So x+z = 180 also

Subtracting the two equations leads to y-z = 0 and y = z. So effectively we've proven the vertical angle theorem.

Since the supplementary angles to x add to 100, we know that y+z = 100. Plug in y = z and solve for z

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I think that a equals to -2.7678571428

Anyways heyy!!!:)

8 0
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