Answer:
25 cm³
Explanation:
In the conversion of units, we know that are one cubic centimeters (cm³) in a milliliter (mL) .
1 milliliter = 1 cubic centimeter
25 milliliters = 25 cubic centimeters
Therefore, a volume of 25 milliliters is the same as a volume of 25 cubic centimeters.
This ultimately implies that, the volume of an object in milliliters is equivalent to its volume in cubic centimeters.
Answer:
a) P' = P_original, b) P ’= P_original + ρ g Δh
Explanation:
The expression for nanometric pressure is
P = ρ g h
where ρ is the density of the liquid and h is the height
a) we change the radius of the barrel, but keeping the same height
as the pressure does not depend on the radius it remains the same
P' = P_original
b) We change the barrel height
h ’≠ h
we substitute in the equation
P ’= ρ g h’
h ’= h + Δh
P ’= ρ g (h + Δh)
P ’= (ρ g h) + ρ g Δh
P ’= P_original + ΔP
In this case, the pressure changes due to the new height,
*if it is higher than the initial one, the pressure increases
*if the height is less than the initial one, the pressure is less
Answer:
B. Ball Y will travel at a speed less than 5 m/s in the opposite direction of travel as before the collision.
Explanation:
Impulse created by ball Y on ball X = 40 x 1/6 Ns
Ball X will also create impulse 40 / 6 on ball Y .
impulse = change in momentum .
impulse in Y = change in momentum in Y .
Initial momentum of Y = .5 x 5 = 2.5
Let final velocity of Y after collision be v in opposite direction .
change in momentum of Y = v - (-2.5 )
so,
v + 2.5 = 40 / 6 = 6.67
v = 4.17 m / s .
Option B is correct .
B. Ball Y will travel at a speed less than 5 m/s in the opposite direction of travel as before the collision.
Answer: a) C decreases; b) Q stays the same; c) E is the same
d) ΔV increase
Explanation: In order to explain this problem we have to consider the following:
C=εoA/d where A and d are the area and the separation of the plates, respectively.
Increasing d, produces a decrease of C.
Q remain constant becasuse the plates are charges and the wire are isoloted each other.
We also know that ΔV=E*d where E is electric field between the plates.
And E= Q/εo*A ( a constant between the plates)
As we can see from above, ΔV depends directely of the d so if d increase ΔV also increase. To do that we have to do work on the system.
