Weight Force of Junior = m g = 115kg x 9.81 m/s^2 = 1128.15N then
compute for the friction force
Friction Force= WF x (coefficient of kinetic friction) = 1128.15N x 0.35 = 394.8525N or 395N
But you can compute in a straightway:
Solution:
= 115 x 9.81 x 0.35
= 394.85
= 395 N
It will still give the same results.
Answer:
kg m/s
Explanation:
e = Charge = C
V = Voltage = 
c = Speed of light = m/s
Momentum is given by
The unit of MeV/c in SI fundamental units is kg m/s
N2+3H2->2NH3
When 3 moles of H2 react, they produce 2 moles of NH3
3 moles of H2 have a mass of 2.02 g
2 moles of NH2 have a mass of 17.0 g
So when 2.02 g H2 react, they produce 17.0 g NH3
If 26.3g H2 react with a yield of 100%, we expect…
2.02g H2_____17.0gNH3
26.3g H2_____x=221gNH3
So now let’s calculate the percentage:
221gNH3_________100%
79.0gNH3_________x=79.0*100/221=35.7%
Nuclear Reactor is made to use the energy which is released due to nuclear fission reaction.
These chain reactions are very fast and they are used with some components which can control these reactions otherwise these reaction will start with high rate and could not be controlled after that.
In order to control these reactions we need to control the high energy particles which can stimulate these reactions
These are neutrons which act as catalyst of these nuclear reactions and these reactions can be control by controlling the numbers of neutrons
These neutrons can be absorbed by some mechanism and the rods which are used to absorb these high energy neutrons are known as control rods.
So correct answer must be control rods
