Answer:
ectron's further from the nucleus are held more weakly by the nucleus, and thus can be removed by spending less energy. Hence we say they have higher energy. The Coulomb interaction energy between a nucleus of atomic number and an ele
Answer:
F = 0i (in the x-direction), 0j (in the y-direction),-8.59*10^-4 N k (In the z-direction)
Explanation:
The force given by charged particles moving in a magnetic field is given below (cross is cross product, they don't have that format in the equation tool):
Now we can perform the cross product between v and B
![v(cross)B = \left[\begin{array}{cc}4.19*10^{4} &-3.85*10^{4}\\1.8&0&\en[tex]v(cross)B = 69300 (kg*m/(s^2*C))\\](https://tex.z-dn.net/?f=v%28cross%29B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D4.19%2A10%5E%7B4%7D%20%26-3.85%2A10%5E%7B4%7D%5C%5C1.8%260%26%5Cen%5Btex%5Dv%28cross%29B%20%3D%2069300%20%28kg%2Am%2F%28s%5E2%2AC%29%29%5C%5C)
d{array}\right][/tex]
Now multiply by Q (charge) to get the force
F = -8.59*10^-4 N k
F = 0i, 0j, (-8.59*10^-4)k
On the map red bands represent the earthquake
Answer:
Explanation:
Make up a question.
The only change is going to be c.
Suppose they aluminum starts our higher at 50oC
Suppose the copper starts out at 20oC
Suppose the mass of both are 25 grams.
Aluminum
m*2c * deltat
- deltat = 50 - x
- c = 2*c
- m = 25
Copper
m*c*deltat
deltat = x - 20
m = 25
c = c
Now since the amount of heat is the same (this starts out on a heated slab of something).
m*2c * (50 - x) = m * c * x - 20 The m and the c are the same. Cancel them out.
2 * (50 - x) = (x - 20) Remove the brackets.
100 - 2x = x - 20 Add 20 to both sides.
120 - 2x = x Add 2x to both sides.
120 = 3x Divide by 3
x = 40
What does this tell you?
It tells you that the temperature of the aluminum is only going to drop 10 degrees
The copper is going to gain 40 - 20 = 20 degrees.
The heat transfer is actually the same. It doesn't take as much heat to heat copper as it does aluminum. That's shown by the difference in how the temperature changes. One looses 10 degrees. The other gains 20. The transfer is the same because of the way the "c" operates.
